Mysql 如何显示计算的休假时间？

在MySQL数据库中，我已将数据插入到“leaves”表中：

+--------+---------+---------+-------------------------------+-----
|Id_LEAVE|ID_WORKER|    BEGIN_DATE        | END_DATE              | 
+--------+---------+------------+--------------------+------------+
| 4      |   26    | 2019-03-19 07:00:00  |2019-03-19 15:00:00    |
+--------+---------+---+----------------------+-------------------+ 
| 5      |   25    | 2019-03-20 07:00:00  |2019-03-21 15:00:00    |
+--------+---------+---------+----------------------+-------------+
| 6      |   21    | 2019-03-22 07:00:00  |2020-03-22 15:00:00    |
+--------+---------+---------+----------------------+-------------+ 

然后，我想显示所有带有计算的休假时间，但没有

time\u格式

和

SEC\u to\u时间

，因为我知道它有一个值限制。当我执行以下代码时：

select
  ID_LEAVE, ID_WORKER, BEGIN_DATE, END_DATE,
  concat_ws(' ',
    concat((sec DIV 60*60), 'h'),
    concat((sec DIV 60) % 60, 'm'),
    concat(sec % 60, 's')
  ) AS 'LEAVE TIME'
from (
select
  SUM(
    to_seconds(
      TIMEDIFF(END_DATE, BEGIN_DATE)
    )
  ) sec,
    ID_LEAVE,
    ID_WORKER,
    BEGIN_DATE,
    END_DATE
from
  leaves group by ID_LEAVE
) s;

然后，我显示所有这些值，但在“离开时间”列中，仅显示空值：

+--------+---------+---------+------------+-----------------------+-----------+
|Id_LEAVE|ID_WORKER|    BEGIN_DATE        | END_DATE              |LEAVE_TIME | 
+--------+---------+------------+--------------------+------------+-----------+
| 4      |   26    | 2019-03-19 07:00:00  |2019-03-19 15:00:00    |           |
+--------+---------+---+----------------------+-------------------+-----------+
| 5      |   25    | 2019-03-20 07:00:00  |2019-03-21 15:00:00    |           |
+--------+---------+---------+----------------------+-------------+-----------+
| 6      |   21    | 2019-03-22 07:00:00  |2020-03-22 15:00:00    |           |
+--------+---------+---------+----------------------+-------------+-----------+

---

我有一个问题：不显示休假时间值的错误在哪里。我应该修复哪行Mysql代码？谢谢你的帮助

试试看，也许会有帮助

SELECT *,FROM_UNIXTIME(
    UNIX_TIMESTAMP(
        TIMEDIFF(END_DATE,BEGIN_DATE)
    ),
    '%h Hours,%i Minutes,%s Seconds') 
    as 'LEAVE TIME' 
FROM `leaves`

---

试试看，也许会有帮助

SELECT *,FROM_UNIXTIME(
    UNIX_TIMESTAMP(
        TIMEDIFF(END_DATE,BEGIN_DATE)
    ),
    '%h Hours,%i Minutes,%s Seconds') 
    as 'LEAVE TIME' 
FROM `leaves`

---

上面写的查询在我这边起作用了，你能在发出查询后尝试显示警告吗？这可能与您这边的sql_模式有关或类似。上面编写的查询在我这边有效，您可以在发出查询后尝试显示警告吗？它可能与您这边的sql_模式有关，或者类似的东西。