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Php 查询生成器自定义on子句_Php_Mysql_Symfony_Doctrine Orm_Shopware - Fatal编程技术网

Php 查询生成器自定义on子句

Php 查询生成器自定义on子句,php,mysql,symfony,doctrine-orm,shopware,Php,Mysql,Symfony,Doctrine Orm,Shopware,我想将下面的SQL语句映射到 select address.*, (CASE WHEN (customer.default_billing_address_id = address.id) THEN 1 ELSE 0 END) as isDefaultBillingAddress, (CASE WHEN (customer.default_shipping_address_id = address.id) THEN 1 ELSE 0 END) as isDefaultS

我想将下面的SQL语句映射到

select 
    address.*,
    (CASE WHEN (customer.default_billing_address_id = address.id) THEN 1 ELSE 0 END) as isDefaultBillingAddress,
    (CASE WHEN (customer.default_shipping_address_id = address.id) THEN 1 ELSE 0 END) as isDefaultShippingAddress
from 
    s_user customer
join
    s_user_attributes customerattributes on customerattributes.customer_number = customer.customernumber
join
    s_user_addresses address on address.user_id = customer.id
where customerattributes.userID = 214
但是当我用查询生成器编写我的条令查询时,我得到的查询总是有点不同:

[...]
FROM s_user_addresses s1_
[...]
INNER JOIN s_user_attributes s5_ ON s0_.id = s5_.userID
INNER JOIN s_user s0_ ON s0_.id = s5_.userID
AND (s5_.customer_number = s0_.customernumber)
WHERE s5_.userID = 214
ORDER BY sclr_0 DESC
  ,sclr_1 DESC
最后,这是使用查询生成器的代码:

$builder->from(Address::class, 'address')
    ->andWhere('customerAttribute.customerId = :userId')
    ->setParameter('userId', $userId)
    ->join('address.customer', 'customer')
    ->join('customer.attribute', 'customerAttribute', Join::WITH, 'customerAttribute.customerNumber = customer.number')
    ->addSelect([
        '(CASE WHEN (customer.defaultBillingAddress = address.id) THEN 1 ELSE 0 END) as HIDDEN isDefaultBillingAddress',
        '(CASE WHEN (customer.defaultShippingAddress = address.id) THEN 1 ELSE 0 END) as HIDDEN isDefaultShippingAddress',
    ])
    ->addOrderBy('isDefaultBillingAddress', 'DESC')
    ->addOrderBy('isDefaultShippingAddress', 'DESC');

问题是,JOIN子句得到了一个,我只想让customer_number得到连接,而不是id的

这两个条件都是在按关系连接时添加的-这会添加映射关系的默认条件


只需将“customer.attribute”更改为实体的全名,我猜类似于CustomerAttribute::class。

为什么和where以及not where?@JustOnUnderMillions应该不会有什么区别。@Fabian Picone那么就不需要两个方法了,或者说?@JustOnUnderMillions与原始代码一样。我只是改变了条件。