如何在php中显示特定时间段之间的任何内容？
我有一个php代码，如下所示，我想在其中显示一周中两个日历日之间的任何内容如何在php中显示特定时间段之间的任何内容？,php,date,if-statement,time,and-operator,Php,Date,If Statement,Time,And Operator,我有一个php代码，如下所示，我想在其中显示一周中两个日历日之间的任何内容 $data->{“选择开始日”}中的值$data->{“开始时间”}$data->{“选择结束日期”}和$data->{“结束时间”}由用户控制 PHP代码： if (file_exists('feeds/ptp-ess_landing.json')) { $data = json_decode(file_get_contents('feeds/ptp-ess_landing.json')); }
$data->{“选择开始日”}中的值$data->{“开始时间”}$data->{“选择结束日期”}和$data->{“结束时间”}由用户控制
PHP代码：
if (file_exists('feeds/ptp-ess_landing.json')) {
$data = json_decode(file_get_contents('feeds/ptp-ess_landing.json'));
}
date_default_timezone_set('America/Toronto');
$arradate = strtolower(date('D'));
$nowtime = (int)date('His');
$start_day=$data->{"select_start_day"};
$start_time=$data->{"start_time"};
$end_day=$data->{"select_end_day"};
$end_time=$data->{"end_time"};
$dowMap = ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat'];
$arradate = date('D');
$arradateNum = array_search($arradate, $dowMap);
$start_dayNum = array_search($start_day, $dowMap);
$end_dayNum = array_search($end_day, $dowMap);
if(
($arradateNum >= $start_dayNum && $nowtime>=$data->{"start_time"}) &&
($arradateNum <= $end_dayNum && $nowtime <= $data->{"end_time"})
) {
echo "Show Anything";
}
例如，假设用户输入$start\u day
作为sun
$start\u time
as143400
$end\u day
aswed
$end\u time
as140000
上面的持续时间意味着我们在范围内，它应该显示我们想显示的任何东西，直到明天下午2点，因为明天是星期三。我在东部时间
我使用以下代码来提取一周中的当前日期和时间：
date_default_timezone_set('America/Toronto');
$arradate = strtolower(date('D'));
$nowtime = (int)date('His');
问题陈述：
我想知道如果我需要使用逻辑，以便它可以打印任何Sunday
143400
和suday
140000
if() {
echo "Its in range";
}
案例：
if (file_exists('feeds/ptp-ess_landing.json')) {
$data = json_decode(file_get_contents('feeds/ptp-ess_landing.json'));
}
date_default_timezone_set('America/Toronto');
$arradate = strtolower(date('D'));
$nowtime = (int)date('His');
$start_day=$data->{"select_start_day"};
$start_time=$data->{"start_time"};
$end_day=$data->{"select_end_day"};
$end_time=$data->{"end_time"};
$dowMap = ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat'];
$arradate = date('D');
$arradateNum = array_search($arradate, $dowMap);
$start_dayNum = array_search($start_day, $dowMap);
$end_dayNum = array_search($end_day, $dowMap);
if(
($arradateNum >= $start_dayNum && $nowtime>=$data->{"start_time"}) &&
($arradateNum <= $end_dayNum && $nowtime <= $data->{"end_time"})
) {
echo "Show Anything";
}
如果覆盖应在周一上午8点到周一下午6点应用，而今天是周三，则覆盖不适用
如果是星期一下午6点和星期五下午6点，则覆盖将在星期一、星期二全天、星期三全天、星期四全天、星期五至下午6点工作
如果是星期日下午6点和星期一下午6点，则覆盖将在星期一工作6小时，星期一工作18小时
如果是星期二下午6点和星期五下午6点，而今天是星期二晚上9点，则将应用覆盖
如果是周四下午6点和周三下午6点，则覆盖将在周四的6小时、周五的24小时、周六的24小时、周日的24小时、周一的24小时、周二的24小时工作，周三24小时和周四18小时
我会保持所有日期的格式相同。Unix时间是存储时间的好方法，因为您可以轻松地运行计算
在您的示例中，您同时使用字符串和数字进行计算。事实上，你有三种不同的方式来表达日期。我建议使用just date（）保存和比较所有值，并在向最终用户显示时仅格式化Unix时间戳
↓↓↓↓ 新编辑↓↓↓
仔细查看代码返回的内容：
$arradate = strtolower(date('D')); //echos the day ex: sun
$nowtime = (int)date('His'); //echos a different format ex: 25019
并仔细阅读函数的文档，特别是您为nowtime选择的参数，这些参数是“他的”，将返回：
H一小时的24小时格式，前导零00到23
i前导零为00到59的分钟数
s秒，前导零00到59
现在考虑DATE（）返回一个时间戳，你会看到失败。您只需删除所有代码中的日期格式，保存显示给最终用户的元素。知道今天是星期三对计算机没有好处。这台计算机从1970年起才开始计数
因此，您只需要一个参数来调用当前日期。这两种方法都有效：
$arradate = date();
$nowtime = date();
最后，在阅读了Unix时间之后，您将看到存储的日期是向后的。您的结束时间是第0天，开始时间是第0天之后的两天 试试这个：
if (file_exists('feeds/ptp-ess_landing.json')) {
$data = json_decode(file_get_contents('feeds/ptp-ess_landing.json'));
}
date_default_timezone_set('America/Toronto');
$arradate = strtolower(date('D'));
$nowtime = (int)date('His');
$start_day=$data->{"select_start_day"};
$start_time=$data->{"start_time"};
$end_day=$data->{"select_end_day"};
$end_time=$data->{"end_time"};
$dowMap = ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat'];
$arradate = date('D');
$arradateNum = array_search($arradate, $dowMap);
$start_dayNum = array_search($start_day, $dowMap);
$end_dayNum = array_search($end_day, $dowMap);
if(
($arradateNum >= $start_dayNum && $nowtime>=$data->{"start_time"}) &&
($arradateNum <= $end_dayNum && $nowtime <= $data->{"end_time"})
) {
echo "Show Anything";
}
$dowMap=['Sun'，'Mon'，'Tue'，'Wed'，'Thu'，'Fri'，'Sat']；
$arradate=日期（'D'）；
$arradateNum=数组搜索（$arradate，$dowMap）；
$start\u dayNum=array\u search（$start\u day，$dowMap）；
$end\u dayNum=数组搜索（$end\u day，$dowMap）；
如果(
（$arradateNum>=$start\U dayNum&&$nowtime>=$data->{“start\U time”}）和
（$arradateNum您应该仔细阅读PHP手册，了解如何创建DateTime对象和各种可用的日期格式
首先，您需要将用户输入转换为DateTimeObjects
date_default_timezone_set('America/Toronto'); //Setting the Timezone
//These are the User Inputs
$start_day = 'tue';
$start_time = 181300;
$end_day = 'fri';
$end_time = 134500;
//User Input Ends
//Create the Date Time Object for Start and End Date
$startDate = DateTime::createFromFormat ( 'D His', $start_day . ' '. $start_time);
$endDate = DateTime::createFromFormat ( 'D His', $end_day . ' '. $end_time);
您可以在中检查createFromFormat的各种可用选项
现在您有了日期-时间对象，您可以从中获取任何值。让我们以数字格式获取一周中的日期，以及以数字格式获取开始日期和结束日期的小时
$startHour = $startDate->format('G'); //24-hour format of an hour without leading zeros
$startDay = $startDate->format('N'); //numeric representation of the day of the week
$endHour = $endDate->format('G'); //24-hour format of an hour without leading zeros
$endDay = $endDate->format('N'); //numeric representation of the day of the week
您可以查看G
和N
格式以及中提供的其他选项
我们需要检查时间是星期二下午6点到星期五下午6点之间
首先，我们将检查这一天是否在星期二和星期五之间。我们有上面的$startDay
和$endDay
变量来确定这一点。
对于星期二，对应的数值为2，对于星期五，对应的数值为5
对于时间范围，我们有$startHour
和$endHour
变量。格式中的6PM表示为18（12+6）
因此，我们可以使用以下代码检查此情况：
if ( $startDay >= 2 && $endDay <= 5 && $startHour >= 18 and $endHour <= 18 ) {
echo 'In Range';
} else {
echo 'out of Range';
}
if（$startDay>=2&&$endDay=18和$endHour这是我的尝试，使用映射表和字符串连接。如果日期顺序相反，则它不起作用。例如，如果今天是星期天，而选择开始日
的值是周五
而选择结束日
的值是周一
，则它不起作用
<?php
$arr = (object) [
'select_start_day' => 'wed',
'start_time' => 143400,
'select_end_day' => 'wed',
'end_time' => 220000
];
$map_daysToNumbers = ['sun'=>1, 'mon'=>2, 'tue'=>3, 'wed'=>4, 'thu'=>5, 'fri'=>6, 'sat'=>7];
$startString = $map_daysToNumbers[$arr->select_start_day] . str_pad($arr->start_time, 6, '0', STR_PAD_LEFT);
$endString = $map_daysToNumbers[$arr->select_end_day] . str_pad($arr->end_time, 6, '0', STR_PAD_LEFT);
$tz = new \DateTimeZone('America/Toronto');
$today = new \DateTime('now', $tz);
$todayString = ($today->format('w')+1) . $today->format('His');
if($startString <= $todayString && $todayString <= $endString){
echo 'In range';
}
这个问题的难点在于处理在周末“环绕”的范围，即您的示例案例5
我建议建立一个涵盖两周的参考日数组
$days = ['mon', 'tue', 'wed', 'thu', 'fri', 'sat', 'sun'];
$days = array_merge($days, $days);
对其进行切片，使其在开始点的当天开始（将从0重新编制索引）
然后可以构建一个引用整数
$nowDay = $arradate;
$nowTime = $nowtime;
$startDay = $start_day;
$startTime = $start_time;
$endDay = $end_day;
$endTime = $end_time;
class WeekDayTime
{
/** @var string[] map of the name of days and their number */
const DAY_MAP = [
'Mon' => 1,
'Tue' => 2,
'Wed' => 3,
'Thu' => 4,
'Fri' => 5,
'Sat' => 6,
'Sun' => 7
];
/** @var int number of the day */
private $dayNumber;
/** @var int amount of hours */
private $hours;
/** @var int amount of minutes */
private $minutes;
/** @var int amount of seconds */
private $seconds;
/**
* Constuctor
* @param string $day number of the day
* @param int $hours amount of hours
* @param int $minutes amount of minutes
* @param int $seconds amount of seconds
*/
public function __construct(string $day, int $hours, int $minutes, int $seconds)
{
assert(array_key_exists($day, static::DAY_MAP), 'The day is incorrect');
assert($hours < 24, 'The hours must be less than 24');
assert($minutes < 60, 'The hours must be less than 60');
assert($seconds < 60, 'The hours must be less than 60');
$this->dayNumber = static::DAY_MAP[$day];
$this->hours = $hours;
$this->minutes = $minutes;
$this->seconds = $seconds;
}
/**
* Get number of the day
* @return int number of the day
*/
public function getDayNumber(): int
{
return $this->dayNumber;
}
/**
* Get amount of hours
* @return int amount of hours
*/
public function getHours(): int
{
return $this->hours;
}
/**
* Get amount of minutes
* @return int amount of minutes
*/
public function getMinutes(): int
{
return $this->minutes;
}
/**
* Get amount of seconds
* @return int amount of seconds
*/
public function getSeconds(): int
{
return $this->seconds;
}
/**
* Check if the current week day time is less the a denined week day time
* @param WeekDayTime $value value which will be compared
* @return bool status of the checking
*/
public function isLessOrEqual(WeekDayTime $value): bool
{
$isLess = $this->dayNumber < $value->dayNumber;
$isLessOrEqual = $this->dayNumber === $value->getDayNumber()
&& $this->hours <= $value->getHours()
&& $this->minutes <= $value->getMinutes()
&& $this->seconds <= $value->getSeconds();
return $isLess || $isLessOrEqual;
}
/**
* Check if the current week day time is greater the a denined week day time
* @param WeekDayTime $value value which will be compared
* @return bool status of the checking
*/
public function isGreaterOrEqual(WeekDayTime $value): bool
{
$isGreater = $this->dayNumber > $value->dayNumber;
$isGreaterOrEqual = $this->dayNumber === $value->getDayNumber()
&& $this->hours >= $value->getHours()
&& $this->minutes >= $value->getMinutes()
&& $this->seconds >= $value->getSeconds();
return $isGreater || $isGreaterOrEqual;
}
}
class WeekDayTimeRange
{
/** WeekDayTime range start */
private $start;
/** WeekDayTime range end */
private $end;
/**
* Constuctor
* @param WeekDayTime $start range start
* @param WeekDayTime $end range end
*/
public function __construct(WeekDayTime $start, WeekDayTime $end)
{
$this->start = $start;
$this->end = $end;
}
/**
* Check if a date-time occurs into the range
* @param DateTimeInterface the date-time which will be checked
* @return bool status of the checking
*/
public function inRange(DateTimeInterface $dateTime): bool
{}
}
public function inRange(DateTimeInterface $dateTime): bool
{
$day = $dateTime->format('D');
$hours = $dateTime->format('H');
$minutes = $dateTime->format('i');
$seconds = $dateTime->format('s');
$weekDayTime = new WeekDayTime($day, $hours, $minutes, $seconds);
return $this->start->isLessOrEqual($weekDayTime) && $this->end->isGreaterOrEqual($weekDayTime);
}
public function inRange(DateTimeInterface $dateTime): bool
{
$day = $dateTime->format('D');
$hours = $dateTime->format('H');
$minutes = $dateTime->format('i');
$seconds = $dateTime->format('s');
$weekDayTime = new WeekDayTime($day, $hours, $minutes, $seconds);
// if the range end is less then range start we break the current range to two range
if ($this->end->isLessOrEqual($this->start)) {
$range1 = new WeekDayTimeRange($this->start, new WeekDayTime('Sun', 23,59,59));
$range2 = new WeekDayTimeRange(new WeekDayTime('Mon', 0,0,0), $this->end);
return $range1->inRange($dateTime) || $range2->inRange($dateTime);
}
return $this->start->isLessOrEqual($weekDayTime) && $this->end->isGreaterOrEqual($weekDayTime);
}
// Date occurs into the range from Tuesday to Friday
$start = new WeekDayTime('Tue', 10, 0,0);
$end = new WeekDayTime('Fri', 14, 0,0);
$range = new WeekDayTimeRange($start, $end);
$range->inRange(DateTime::createFromFormat('Y-m-d H:i:s', '2019-10-03 10:00:00'));
// Date doesn't occur into the range from Tuesday to Friday
$start = new WeekDayTime('Tue', 10, 0,0);
$end = new WeekDayTime('Fri', 14, 0,0);
$range = new WeekDayTimeRange($start, $end);
$range->inRange(DateTime::createFromFormat('Y-m-d H:i:s', '2019-10-05 10:00:00'));
// Date doesn't occur into the range from Friday to Tuesday
$start = new WeekDayTime('Fri', 14, 0,0);
$end = new WeekDayTime('Tue', 10, 0,0);
$range = new WeekDayTimeRange($start, $end);
$range->inRange(DateTime::createFromFormat('Y-m-d H:i:s', '2019-10-03 10:00:00'));
// Date occurs into the range from Friday to Tuesday
$start = new WeekDayTime('Fri', 14, 0,0);
$end = new WeekDayTime('Tue', 10, 0,0);
$range->inRange(DateTime::createFromFormat('Y-m-d H:i:s', '2019-10-05 10:00:00'));
date_default_timezone_set('America/Toronto');
$now = new DateTime();
$date = $now->format('Y-m-d');
$time = $now->format('h:i A');
$dayname = strtolower(date('l', strtotime($date))); //it will give you today's day name
$start_day = "monday"; //lets consider your data will be come as startday="monday" from $data->{"select_start_day"};
$start_time = '07:50 AM'; //lets consider your data will be come as starttime="07:50 AM" from $data->{"start_time"};
$end_day = "tuesday"; //lets consider your data will be come as endday="monday" from $data->{"select_end_day"};
$end_time = '08:26 AM'; //lets consider your data will be come as endtime="08:26 AM" from $data->{"end_time"};
$todays_date_time = strtotime($dayname);
$start_day_time = strtotime($start_day);
$end_day_time = strtotime($end_day);
$timeconvert = strtotime($time);
$timeconvertstart = strtotime($start_time);
$timeconvertend = strtotime($end_time);
if($todays_date_time >= $start_day_time && $todays_date_time <= $end_day_time )
{
if ($timeconvert >= $timeconvertstart && $timeconvert <= $timeconvertend) {
echo "test";
}
}