Php Codeigniter将数组从控制器传递到模型,但不返回匹配结果
我正在尝试将一组数据从控制器发送到模型。但当我在控制器上打印时,我没有得到相应“已用id”的匹配“员工代码” 我的控制器Php Codeigniter将数组从控制器传递到模型,但不返回匹配结果,php,mysql,codeigniter,Php,Mysql,Codeigniter,我正在尝试将一组数据从控制器发送到模型。但当我在控制器上打印时,我没有得到相应“已用id”的匹配“员工代码” 我的控制器 Controller: $get_userid = $this->report->get_users_from_manager_id($this->session_user_id); $data["permit_user_id"] = $get_userid; foreach($get_userid as $user){ $
Controller:
$get_userid = $this->report->get_users_from_manager_id($this->session_user_id);
$data["permit_user_id"] = $get_userid;
foreach($get_userid as $user){
$data["get_employee_code"] = $this->report->get_user_employee_code($user['user_id']);
}
我的模型:
Model:
/**Get User_id From the Manager id */
public function get_users_from_manager_id($manager_d){
// $output = array();
$sql = 'SELECT * FROM manager WHERE manager_id = "'.$manager_d.'"';
$query = $this->db->query($sql);
if ($query->num_rows() > 0) {
$data = $query->result_array();
}
return $data;
}
public function get_user_employee_code($user_id)
{
$sql = 'SELECT * FROM user WHERE user_id = "'.$user_id.'"';
$query = $this->db->query($sql);
if ($query->num_rows() > 0) {
$data = $query->result_array();
}
return $data;
}
我的看法:
Views:
foreach($permit_user_id as $user){
foreach($get_employee_code as $employee_code){
print_r("User_id:".$user['user_id']." Employee_code:".$employee_code['employee_code']."<br>");
}
}
表用户:
id user_id employee_code
1 10001 500001
2 10002 500002
3 10003 500003
4 10004 500004
5 10005 500005
6 10006 500006
输出我得到的
User_id: 10001 Employee_code: 500006
User_id: 10002 Employee_code: 500006
User_id: 10003 Employee_code: 500006
User_id: 10004 Employee_code: 500006
User_id: 10005 Employee_code: 500006
User_id: 10006 Employee_code: 500006
输出我需要的内容:
User_id: 10001 Employee_code: 500001
User_id: 10002 Employee_code: 500002
User_id: 10003 Employee_code: 500003
User_id: 10004 Employee_code: 500004
User_id: 10005 Employee_code: 500005
User_id: 10006 Employee_code: 500006
提前感谢这是您弄错的地方:
foreach($get\u userid作为$user){
$data[“get_employee_code”]=$this->report->get_user_employee_code($user['user_id');
}
在这里,您将在每次迭代中覆盖$data[“get\u employee\u code”]
。最后,这个数组中剩下的就是最后一个值“500006”。你可能想做的是:
$data["get_employee_code"][] = // <- note the extra brackets
您应该做的是编写一个查询来获取模型中所需的所有数据,而不是所有这些:
public函数从\u经理\u id($manager\u id)获取\u用户\u和\u员工\u id\u{
$sql='在user.user\u id=manager.user\u id其中manager.manager\u id=“”.$manager\u id.”上从用户加入管理器中选择user.user\u id、user.employee\u id;
$query=$this->db->query($sql);
如果($query->num\u rows()>0){
$data=$query->result_array();
}
返回$data;
}
现在,这个$data
是一个数组,它包含带有成对用户和员工ID的行,您可以将这些行传递到视图中,只需使用单个foreach
即可输出
另外,我不知道在后台数据库查询使用了什么,但是找到了一种方法来参数化查询。直接将参数插入这样的查询中。尝试在单个查询中实现这一点可以减少不必要的循环和数据库调用
SELECT
a.`manager_id`,
a.`user_id`,
b.`employee_code`
FROM
`manager` AS a
INNER JOIN `user` AS b
ON a.`user_id` = b.`user_id`
ORDER BY a.`manager_id` ASC,
a.`id` ASC ;
一旦到达要查看的数据
你可以用
或
- 为manager\u id声明数组
- 循环结果
- 您可以通过签入数组调用来区分管理器id
$user\u id.
而不是变量值。@T.Maharani您能用任何示例解释我吗
User_id: 10001 Employee_code: 500001
User_id: 10001 Employee_code: 500002
User_id: 10001 Employee_code: 500003
User_id: 10001 Employee_code: 500004
User_id: 10001 Employee_code: 500005
User_id: 10001 Employee_code: 500006
User_id: 10002 Employee_code: 500001
User_id: 10002 Employee_code: 500002
User_id: 10002 Employee_code: 500003
User_id: 10002 Employee_code: 500004
User_id: 10002 Employee_code: 500005
User_id: 10002 Employee_code: 500006
... and so on ...
SELECT
a.`manager_id`,
a.`user_id`,
b.`employee_code`
FROM
`manager` AS a
INNER JOIN `user` AS b
ON a.`user_id` = b.`user_id`
ORDER BY a.`manager_id` ASC,
a.`id` ASC ;