PHP MySQL JSON更新
我在更新MySQL5.7.xjson数据时遇到问题 我在field activities中存储了以下JSON。我想搜索结果为_id=418的活动 我的表2017_评估_数据有一条记录,其中包含student_id字段(值3531)和activities JSON字段,其中包含以下数据:PHP MySQL JSON更新,php,mysql,json,Php,Mysql,Json,我在更新MySQL5.7.xjson数据时遇到问题 我在field activities中存储了以下JSON。我想搜索结果为_id=418的活动 我的表2017_评估_数据有一条记录,其中包含student_id字段(值3531)和activities JSON字段,其中包含以下数据: { "course": "ENGLISH", "level" : "2", "activities": [ { "comments":
{
"course": "ENGLISH",
"level" : "2",
"activities": [
{
"comments": "test1",
"outcomes": [
{
"outcome_id": "423",
"course": "ENGLISH",
"course_level": "2",
"internal_outcome_id": "1"
}
],
"activity_name": "Quiz from chapters 1,2",
"date_completed": "20180201"
},
{
"comments": "test1 comments",
"outcomes": [
{
"outcome_id": "421",
"course": "ENGLISH",
"course_level": "2",
"internal_outcome_id": "4"
},
{
"outcome_id": "415",
"course": "ENGLISH",
"course_level": "2",
"internal_outcome_id": "5"
}
],
"activity_name": "Test chapter 4",
"date_completed": "20180201"
},
{
"comments": "test1",
"outcomes": [
{
"outcome_id": "426",
"course": "ENGLISH",
"course_level": "2",
"internal_outcome_id": "4"
},
{
"outcome_id": "418",
"course": "ENGLISH",
"course_level": "2",
"internal_outcome_id": "3"
}
],
"activity_name": "Activity",
"date_completed": "20180201"
},
{
"comments": "",
"outcomes": [],
"activity_name": "NEW",
"date_completed": ""
}
]
}
我在JSON数据的底部添加了一个空的活动,但以后无法编辑这些值
以下是我的PHP代码:
$update = "
UPDATE 2017_assessment_data
SET
assessment_data = JSON_SET(assessment_data,'$.activities.activity_name','NEW ACTIVITY NAME')
WHERE
student_id = '3531'
AND
JSON_EXTRACT(assessment_data, '$.course') = 'ENGLISH'
AND
JSON_EXTRACT(assessment_data, '$.level') = '2'
AND
JSON_EXTRACT(assessment_data, '$.activities[*].activity_name') = 'NEW'
";
有什么想法吗 这可以使用MySQL JSON函数来完成。您的查询略有不同:
UPDATE 2017_assessment_data
SET assessment_data = JSON_SET(assessment_data, TRIM('"' FROM JSON_SEARCH(assessment_data, 'one', 'NEW')), 'NEW ACTIVITY NAME')
WHERE student_id = '3531' AND
JSON_EXTRACT(assessment_data, '$.course') = 'ENGLISH' AND
JSON_EXTRACT(assessment_data, '$.level') = '2' AND
JSON_SEARCH(assessment_data, 'one', 'NEW') REGEXP '^"\\$\\.activities\\[[0-9]+\\]\\.activity_name"$'
区别在于:
WHERE
子句中,我们使用JSON\u SEARCH
并使用REGEXP
检查是否存在'NEW'
值,确保它与预期路径匹配SET
子句中,我们使用相同的JSON\u SEARCH
获取要更新的值的路径。请注意,我们必须修剪该值的前导双引号和尾随双引号,因为它们在路径字符串中无效
$sid = 3531;
$course = 'ENGLISH';
$level = 2;
$sql = <<<EOD
UPDATE 2017_assessment_data
SET assessment_data = JSON_SET(assessment_data, TRIM('"' FROM JSON_SEARCH(assessment_data, 'one', 'NEW')), 'NEW ACTIVITY NAME')
WHERE student_id = '$sid' AND
JSON_EXTRACT(assessment_data, '$.course') = '$course' AND
JSON_EXTRACT(assessment_data, '$.level') = '$level' AND
JSON_SEARCH(assessment_data, 'one', 'NEW') REGEXP '^"\\\\$\\\\.activities\\\\[[0-9]+\\\\]\\\\.activity_name"$'
EOD;
echo $sql;
在MYSQL中很有魅力,但是如何让它在PHP中工作呢?双引号“正在引起问题。我试着用\和没有joyHi Paul来逃离它们,请参见我的编辑。我想这对你应该有用。太棒了!从未使用过herdoc,但将:)它现在在PHP中对我有效。很遗憾,我必须使用正则表达式来进行此查询。MYSQL JSON函数似乎不喜欢处理对象数组——更新或搜索。我可以只使用JSON的文本字段和正则表达式。嗨,保罗,我一直在使用正则表达式,如果你确定你不会在JSON的其他地方得到一个包含“NEW”的字段,那么你可以简单地将
REGEXP…
更改为不为NULL
UPDATE 2017_assessment_data
SET assessment_data = JSON_SET(assessment_data, TRIM('"' FROM JSON_SEARCH(assessment_data, 'one', 'NEW')), 'NEW ACTIVITY NAME')
WHERE student_id = '3531' AND
JSON_EXTRACT(assessment_data, '$.course') = 'ENGLISH' AND
JSON_EXTRACT(assessment_data, '$.level') = '2' AND
JSON_SEARCH(assessment_data, 'one', 'NEW') REGEXP '^"\\$\\.activities\\[[0-9]+\\]\\.activity_name"$'