Php 解析日志文件

我有一个日志文件“file.log”。我试图用php解析该文件以获得键值对

Notification: {
"state" : "PROGRESSING",
"version" : "2012-09-25",
"jobId" : "xxxxxxxxx",
"pipelineId" : "xxxxxxxxxxx",
"input" : {
   "key" : "upload2/xxxxx",
   "frameRate" : "auto",
   "resolution" : "auto",
   "aspectRatio" : "auto",
   "interlaced" : "auto",
   "container" : "auto"
 },
"outputKeyPrefix" : "output2/test4/",
"outputs" : [ {
   "id" : "1",
   "presetId" : "xxxxxxxxxxxx",
   "key" : "xxxxxxxx",
   "rotate" : "auto",
   "status" : "Progressing"
    } ]
  }

我已经更改了值。我试图用php代码解析它

<?php
$myFile = "file.log";
$lines = file($myFile);
foreach ($lines as $no => $ln) {
$out = explode(":", $ln);
echo($out[1]);
echo(trim($out[1]));
?>

我得到了我的输出

{{“正在进行”，“正在进行”，“2012-09-25”，“2012-09-25”，“XXXXXXXXXXXXXX”，“xxxxxxxxxx”，“XXXXXXXXXXXXXX”

---

它一直在运行。格式不正确。我想要它作为键值对。如何做？请大家需要帮助！我还需要检索它们并使用mysql将其存储在数据库中。

没关系，如果json文件中没有json字符串。您可以将其解析为-

<?php
$myFile = "file.log";
$json = file_get_contents($myFile);
$json= explode(":",$json,2);
$json=$json[1];
$obj=json_decode($json,true);
print_r($obj);

?>

更新：

$logFile = file_get_contents('logfile.log');

// first we replace all instances of the string "Notification: " with a comma to separate the json objects
$cleanLog = str_replace("Notification: ",",",$logFile);

// next we replace the first comma
$cleanLog = '[' . ltrim($cleanLog,",") . ']';

// construct the list of object
$objects = json_decode($cleanLog);

// use this main loop to iterate over all Notification rows
foreach ($objects as $object){
    // write a mysql insert statement here, 
    // you can address each object and inner members as follows:

    print $object->state . PHP_EOL;
    print $object->outputKeyPrefix . PHP_EOL;
    print $object->outputs[0]->id . PHP_EOL;
    print $object->input->key . PHP_EOL;
}

使用此日志文件示例作为参考：

logfile.log

Notification: {
"state" : "PROGRESSING",
"version" : "2012-09-25",
"jobId" : "xxxxxxxxx",
"pipelineId" : "xxxxxxxxxxx",
"input" : {
   "key" : "upload2/xxxxx",
   "frameRate" : "auto",
   "resolution" : "auto",
   "aspectRatio" : "auto",
   "interlaced" : "auto",
   "container" : "auto"
 },
"outputKeyPrefix" : "output2/test4/",
"outputs" : [ {
   "id" : "1",
   "presetId" : "xxxxxxxxxxxx",
   "key" : "xxxxxxxx",
   "rotate" : "auto",
   "status" : "Progressing"
    } ]
  }
Notification: {
"state" : "PROGRESSING",
"version" : "2012-09-25",
"jobId" : "xxxxxxxxx",
"pipelineId" : "xxxxxxxxxxx",
"input" : {
   "key" : "upload2/xxxxx",
   "frameRate" : "auto",
   "resolution" : "auto",
   "aspectRatio" : "auto",
   "interlaced" : "auto",
   "container" : "auto"
 },
"outputKeyPrefix" : "output2/test4/",
"outputs" : [ {
   "id" : "1",
   "presetId" : "xxxxxxxxxxxx",
   "key" : "xxxxxxxx",
   "rotate" : "auto",
   "status" : "Progressing"
    } ]
  }
Notification: {
"state" : "PROGRESSING",
"version" : "2012-09-25",
"jobId" : "xxxxxxxxx",
"pipelineId" : "xxxxxxxxxxx",
"input" : {
   "key" : "upload2/xxxxx",
   "frameRate" : "auto",
   "resolution" : "auto",
   "aspectRatio" : "auto",
   "interlaced" : "auto",
   "container" : "auto"
 },
"outputKeyPrefix" : "output2/test4/",
"outputs" : [ {
   "id" : "1",
   "presetId" : "xxxxxxxxxxxx",
   "key" : "xxxxxxxx",
   "rotate" : "auto",
   "status" : "Progressing"
    } ]
  }

---

“Notification:”位后的字符串是有效的

json

。您可以按如下方式解析它：

<?php

$string = '{
"state" : "PROGRESSING",
"version" : "2012-09-25",
"jobId" : "xxxxxxxxx",
"pipelineId" : "xxxxxxxxxxx",
"input" : {
   "key" : "upload2/xxxxx",
   "frameRate" : "auto",
   "resolution" : "auto",
   "aspectRatio" : "auto",
   "interlaced" : "auto",
   "container" : "auto"
 },
"outputKeyPrefix" : "output2/test4/",
"outputs" : [ {
   "id" : "1",
   "presetId" : "xxxxxxxxxxxx",
   "key" : "xxxxxxxx",
   "rotate" : "auto",
   "status" : "Progressing"
    } ]
  }';

// construct object  
$object = json_decode($string);

// call each property of the object or inner object

print $object->state . PHP_EOL;
// PROGRESSING

print $object->outputKeyPrefix . PHP_EOL;  
// output2/test4/

print $object->outputs[0]->id . PHP_EOL;
// 1

// or, for multiple outputs

foreach ($object->outputs as $output)
    print $output->rotate . PHP_EOL;
// auto

试试这个：

$myFile = "file.log";
$str = file_get_contents($myFile);
$json = trim(strstr($str, ':'), ': ');
print_r(json_decode($json));// for Object
print_r(json_decode($json, true));// for Array

实际上，“通知”阻止字符串被读取为JSON。因为有效的JSON应该从大括号或方括号开始，
我们首先删除“通知”，然后从字符串的两侧删除多余的空格或双冒号。因此，只剩下有效的JSON。
它看起来像一个JSON文件。使用JSON parsertry with
JSON\u decode（）
一次。我想它是JSON格式的。不。这是一个转码作业的日志文件当我尝试使用JSON decode时，我遇到了这个错误“致命错误：未捕获异常‘InvalidArgumentException’，消息为‘传递的变量不是数组或对象，而是使用空数组’”我不应该删除它们。这就是我获取文件的方式。我不应该每次都进去编辑。你不必删除它们，这段代码会自动删除它们。它跟踪第一次出现的双冒号，然后删除之前的任何“通知”在这种情况下。没有得到任何输出..但是得到了答案。谢谢。如果我使用file_get_contents（$filename）包含该文件，则代码不起作用。我将使用代码更新答案，以正确解析日志文件$string不包含“通知”.String无法编辑，因为它来自一个不需要编辑的文件。我更新了答案以显示如何删除“通知”：部分并最终得到一个有效的
json
字符串。我只假设了一个多条目日志示例的外观，但代码应该足够好以供参考。谢谢。它工作了…-）。现在我如何在mysql中将通知的每个条目保存为一个单独的行。我应该在foreach循环内的mysql中使用insert命令吗？仍然没有t显示输出。谢谢，但我得到了答案：-）