Php 工厂关系返回空laravel测试
我正在尝试对一个服务进行单元测试,该服务处理Laravel中的用户注册 这是服务:Php 工厂关系返回空laravel测试,php,laravel,unit-testing,phpunit,Php,Laravel,Unit Testing,Phpunit,我正在尝试对一个服务进行单元测试,该服务处理Laravel中的用户注册 这是服务: public function completeRegistration(Collection $data) { $code = $data->get('code'); $registerToken = $this->fetchRegisterToken($code); DB::beginTransaction(); $reg
public function completeRegistration(Collection $data)
{
$code = $data->get('code');
$registerToken = $this->fetchRegisterToken($code);
DB::beginTransaction();
$registerToken->update(['used_at' => Carbon::now()]);
$user = $this->userRepository->update($data, $registerToken->user);
$token = $user->createToken(self::DEFAULT_TOKEN_NAME);
DB::commit();
return [
'user' => $user,
'token' => $token->plainTextToken,
];
}
其中,update
方法具有以下签名:
<?php
namespace App\Repositories\User;
use App\Models\User;
use Illuminate\Pagination\LengthAwarePaginator;
use Illuminate\Support\Collection;
interface UserRepositoryInterface
{
public function create(Collection $data): User;
public function update(Collection $data, User $user): User;
}
当我运行phpunit--filter=test\u user\u can\u complete\u registration
时,我得到以下错误:
1) Tests\Unit\Services\Auth\AuthServiceTest::test_user_can_complete_registration
TypeError: Argument 2 passed to Mockery_0_App_Repositories_User_UserRepositoryInterface::update() must be an instance of App\Models\User, null given, called in /var/www/app/Services/Auth/AuthService.php on line 64
/var/www/app/Services/Auth/AuthService.php:64
/var/www/tests/Unit/Services/Auth/AuthServiceTest.php:88
这告诉我,$registerTokenFactory
上的用户关系为空。当我这样做时:
public function test_user_can_complete_registration()
{
...
dd($registerTokenFactory->user);
}
我得到输出null
。我正在尝试在不访问数据库的情况下测试服务。如何将用户
关系附加到$registerTokenFactory
对象?我已尝试将用于
并尝试直接附加:
$registerTokenFactory = RegisterToken::factory()
->for($userFactory)
->timestamped()
->make(['user_id' => $userFactory->id, 'user' => $userFactory]);
在Laravel
factoriesmake()
中,只创建模型,不保存模型。要使关系正常工作,需要保存模型
$userFactory = User::factory()->create();
因为你不想使用数据库,这在我看来是错误的。人们不喜欢编写测试,所以当我们不得不这么做时,让它变得简单,模仿一切来避免数据库是一种痛苦。相反,另一种选择是让您Sqlite
在内存中快速轻松地运行。缺点是一些功能在JSON字段中不起作用,并且大多数Ubuntu发行版中的版本不尊重外键
如果你想沿着你已经在上面的路径走,分配给这个对象上的用户就可以了,我假设你有一些代码的遗漏部分
$userRepositoryMock = Mockery::mock(UserRepositoryInterface::class);
$registerTokenRepositoryMock = Mockery::mock(RegisterTokenRepository::class);
$user = User::factory()->make();
$registerToken = RegisterToken::factory()
->for($userFactory)
->timestamped()
->make(['user_id' => $user->id]);
$registerToken->user = $user;
$registerTokenRepositoryMock
->expects('fetchRegisterToken')
->once()
->andReturn($registerToken);
$userRepositoryMock
->expects($this->any())
->once()
->andReturn($user);
// execute the call
$userRepositoryMock = Mockery::mock(UserRepositoryInterface::class);
$registerTokenRepositoryMock = Mockery::mock(RegisterTokenRepository::class);
$user = User::factory()->make();
$registerToken = RegisterToken::factory()
->for($userFactory)
->timestamped()
->make(['user_id' => $user->id]);
$registerToken->user = $user;
$registerTokenRepositoryMock
->expects('fetchRegisterToken')
->once()
->andReturn($registerToken);
$userRepositoryMock
->expects($this->any())
->once()
->andReturn($user);
// execute the call