关于连接的PHP MySQL查询

我有一个新的PHP MySQL问题，我有2个表、成员和消息

表“成员”

+-----------+------+
| MEMBER_ID | NAME |
+-----------+------+
|         1 | Bob  |
|         2 | Ted  |
|         3 | Tom  |
+-----------+------+

表“消息”

+----+------------+--------------+--------------------+
| ID | SENDERS_ID | RECEIVERS_ID |      MESSAGE       |
+----+------------+--------------+--------------------+
|  1 |          1 |            3 | Hello Tom from Bob |
|  2 |          2 |            3 | Hello Tom from Ted |
|  3 |          2 |            1 | Hello Bob from Ted |
+----+------------+--------------+--------------------+

我想在Tom只有成员的情况下进行查询。成员id 可以获取他的所有邮件以及发件人的姓名，如下所示：

+------+--------------------+
| name |      message       |
+------+--------------------+
| Bob  | Hello Tom from Bob |
| Ted  | Hello Tom from Ted |
+------+--------------------+

我读过一些连接示例，但知道如何将它们实现到MySQL语句中

我可以很容易地获得Tom的会员身份证，但不知道如何进一步进行。 我还想以数组的形式返回结果

  public function getMessages($member_id) {

  $result = mysql_query("SELECT member_id FROM members WHERE member_id = '$member_id'") or die(mysql_error());
    $no_of_rows = mysql_num_rows($result);
    if ($no_of_rows > 0) {
        $result = mysql_fetch_array($result); 
        $receivers_id = $result['member_id'];
        .
        // What can I do here to get the $result that I want?
        .
    }
    $no_of_rows = mysql_num_rows($result);
    if ($no_of_rows > 0) {
        $results = array();
        while(list($results) = mysql_fetch_array($result)) {
            array_push($results, $result);
        } 
        return $results;
    }
}       

任何帮助都将不胜感激

谢谢

SELECT  c.name,
        b.message
FROM    members a
        INNER JOIN  messages b
            ON a.member_ID = b.receivers_id
        INNER JOIN members c
            ON b.senders_ID = c.member_ID
WHERE   a.name = 'Tom'

---

谢谢Kuya John，我现在就试用它

+1

，因为它提供了具有所需结果的样本记录，并明确表示：D