wamp服务器未在javascript语句中运行PHP代码
javascript代码中的php返回为php statement,而不是$\u GET值。配置中是否有需要更改的内容?这在大学的apache服务器上是可行的,但在这种情况下似乎不行,PHP和javascript在其他页面上也可以正常工作。删除操作也很好wamp服务器未在javascript语句中运行PHP代码,php,javascript,wamp,wampserver,Php,Javascript,Wamp,Wampserver,javascript代码中的php返回为php statement,而不是$\u GET值。配置中是否有需要更改的内容?这在大学的apache服务器上是可行的,但在这种情况下似乎不行,PHP和javascript在其他页面上也可以正常工作。删除操作也很好 <SCRIPT LANGUAGE="JavaScript"> setTimeout(function(){ alert("<?echo $_GET['deletename']?> Deleted, you wil
<SCRIPT LANGUAGE="JavaScript">
setTimeout(function(){
alert("<?echo $_GET['deletename']?> Deleted, you will now return to the Artist Search...")
window.location = "http://www.aaaaa.tk/CI/index.php/about?deletedartist=<?echo $_GET['deletename']?>";
}, 100);
</script>
<link rel="stylesheet" type="text/css" href="main.css">
</head>
<?php
$artistid = $_GET['deleteid'];
$username="X";
$password="X";
$database="X";
mysql_connect(localhost,$username,$password) or die("Could not connect : " . mysql_error());
@mysql_select_db($database) or die( "Unable to select database");
/* Performing SQL query */
$query = "DELETE FROM fbartist WHERE id =$artistid";
$query2 = "ALTER TABLE fbartist AUTO_INCREMENT=1;";
$result = mysql_query($query) or die("Delete Query failed :".$query."" . mysql_error());
$result2 = mysql_query($query2) or die("Auto Increment Query failed : " . mysql_error());
mysql_close();
?>
setTimeout(函数(){
警报(“已删除,您现在将返回艺术家搜索…”)
window.location=”http://www.aaaaa.tk/CI/index.php/about?deletedartist=";
}, 100);
谢谢你的帮助。试试看
alert("<?php echo ....
alert(“是您的alert
语句后缺少的分号吗?是的,是开头标记缺少的php,我以为我已经完成了所有这些,我的错。谢谢您的帮助。”。