Php 插入或更换编码点火器

如果数据库中存在codeigniter，我想插入替换 这是我的模型

public function upload($id_akun,$data){
               $query = $this->db->query("SELECT * FROM akun WHERE
id_akun = '{$data['id_akun']}' ");
$result = $query->result_array();
$count = count($result);

if (empty($count)) {

     $this->db->insert('foto', $data);  
}
elseif ($count == 1) {
   $this->db->where('id_akun', $data['id_akun']);
                    $this->db->update('foto', $data);  
}

如果存在数据，我会成功地替换（更新）数据，但如果（空（$count））则不会插入数据

有条件（$count==1）--->没问题

---

条件（空（$count））-->问题？

您可以这样尝试

public function upload($id_akun,$data){       
   $this->db->where('id_akun',$data['id_akun']);
   $this->db->from('akun');
   $query = $this->db->get();
   $rowcount = $query->num_rows();

  if ($rowcount==0) {

    $this->db->insert('foto', $data);  
  }
 else {
   $this->db->where('id_akun', $data['id_akun']);
                $this->db->update('foto', $data);  
  }

---

您的问题是正在检查

count（）

的结果是否为空。这将永远被评估为错误

public function upload($id_akun, $data)
{
    //use active record methods, otherwise, you need to sanitize input
    $this->db->select('*');
    $this->db->where('id_akun', $data['id_akun']);
    $query = $this->db->get('akun'); 

    if($query->num_rows() == 0){
        $this->db->update...
    }else{
         ....
    }
}

---

解释

函数result\u array（）如果在获取记录中未找到任何内容，则会生成空数组。因此，当您获取记录时，它将返回空数组，并且您正在计算该空数组，该空数组返回的长度为零，不等于空，因此您的条件始终为false

您可以使用以下代码

代码

     function upload($id_akun, $data) {
       //use active record methods, otherwise, you need to sanitize input
       $this->db->select('*');
       $this->db->where('id_akun', $data['id_akun']);
       $query = $this->db->get('akun');
       if ($query->num_rows() == 0) {

           //write your Insert query here

       } elseif ($query->num_rows() > 0) {

          //write your Update query here 

       }
     }

试试这个

在型号中

public function upload($id_akun,$table){
    $query = $this->db->query("SELECT * FROM akun WHERE id_akun = '$id_akun' ");
    $result = $query->result_array();
    $count = count($result);

    if (empty($count)){
        $this->db->insert('foto', $table);
        return 0; 
    }
    elseif ($count == 1) {
        $this->db->where('id_akun', $id_akun);
        $this->db->update('foto', $table);  
        return 1;
    }
    elseif (($count >= 1) {
        return 2;
    }
}

在控制器中

$id_akun = 25;
$table = 'table_name';

$result = $this->model_name->upload($id_akun,$table);

switch ($result) {
    case 0:
        $output = 'Data Inserted'
        break;
    case 1:
        $output = 'Record Inserted'
        break;
    case 2:
        $output = 'Multiple Record Found'
        break;
}

---

使用Active Record（或即将调用的查询生成器）有几个好处：

保安

代码清洁度

数据库不可知论

所以，始终尝试使用活动记录

<?php
public function upload($id_akun,$data){ 
    $query = $this->db->select('*')->where('id_akun', $data['id_akun'])->from('akun')->get();
    $count = $query->num_rows();
    $result = $query->result_array();

    if ($count == 0)
        return $this->db->insert('foto', $data);
    }
    elseif ($count > 1) {
        $this->db->where('id_akun', $data['id_akun']);
        return $this->db->update('foto', $data);  
    }
}