Php 您的SQL语法有错误；检查手册

您的SQL语法有错误；检查与MySQL服务器版本对应的手册，以了解第4行“WHERE j.

id\u customer

=1”附近使用的正确语法

SELECT j.`id_customer`, j.`id_order`, m.`id_shop`
        FROM `ps_orders` j     
        LEFT JOIN `ps_order_detail` m   
        WHERE j.`id_customer` = 1

如果启用了详细的错误更正，则会从prestashop php on中的原始代码生成此代码-------

---

你的报告中缺少ON子句

因此：

SELECT j.id_customer, j.id_order, m.id_shop FROM ps_orders j
INNER JOIN ps_order_detail m
WHERE j.id_customer = 1

---

但它不适用于外部联接。

链接两个表时，必须在每个表上定义一列来连接它们

您可以在未指定的

JOIN

的

ON

条件下执行此操作。例如：

SELECT *
FROM table1 
LEFT JOIN table2 ON table1.pk_id = table2.fk_id

SELECT j.id_customer, j.id_order, m.id_shop FROM ps_orders j
JOIN ps_order_detail m
WHERE j.id_customer = 1

SELECT j.id_customer, j.id_order, m.id_shop FROM ps_orders j
INNER JOIN ps_order_detail m
WHERE j.id_customer = 1

SELECT *
FROM table1 
LEFT JOIN table2 ON table1.pk_id = table2.fk_id