Php 在Symfony 2.1中为预更新调用添加其他持久化调用
我的应用程序中有一个预更新侦听器。当它被激发时,我希望它创建一些额外的记录。下面是基本功能的简化示例。在当前的实现中,新事件似乎没有被持久化。我还需要打其他电话吗?谢谢Php 在Symfony 2.1中为预更新调用添加其他持久化调用,php,symfony,doctrine,listener,symfony-2.1,Php,Symfony,Doctrine,Listener,Symfony 2.1,我的应用程序中有一个预更新侦听器。当它被激发时,我希望它创建一些额外的记录。下面是基本功能的简化示例。在当前的实现中,新事件似乎没有被持久化。我还需要打其他电话吗?谢谢 public function preUpdate(Event\LifecycleEventArgs $eventArgs) { $em = $eventArgs->getEntityManager(); $uow = $em->getUnitOfWork(); $entity = $even
public function preUpdate(Event\LifecycleEventArgs $eventArgs)
{
$em = $eventArgs->getEntityManager();
$uow = $em->getUnitOfWork();
$entity = $eventArgs->getEntity();
$updateArray = $eventArgs->getEntityChangeSet();
//Updates
if (($entity instanceof Bam) === false) {
$thing = new OtherThing();
$thing->setFoo('bar');
$uow->persist($thing);
}
$uow->computeChangeSets();
}
关键是在刷新后保持它们:
<?php
namespace Comakai\CQZBundle\Handler;
use Symfony\Component\DependencyInjection\ContainerInterface;
use Doctrine\Common\EventSubscriber;
use Doctrine\ORM\Event;
/**
*
*/
class YourHandler implements EventSubscriber
{
protected $things = [];
public function getSubscribedEvents()
{
/**
* @todo Check if this is running in the console or what...
*/
if (isset($_SERVER['HTTP_HOST'])) {
return [
'preUpdate',
'postFlush'
];
}
return [];
}
public function preUpdate(Event\LifecycleEventArgs $eventArgs)
{
$em = $eventArgs->getEntityManager();
$uow = $em->getUnitOfWork();
$entity = $eventArgs->getEntity();
$updateArray = $eventArgs->getEntityChangeSet();
//Updates
if (($entity instanceof Bam) === false) {
$thing = new OtherThing();
$thing->setFoo('bar');
$this->things[] = $thing;
}
}
public function postFlush(Event\PostFlushEventArgs $event)
{
if(!empty($this->things)) {
$em = $event->getEntityManager();
foreach ($this->things as $thing) {
$em->persist($thing);
}
$this->things = [];
$em->flush();
}
}
}
什么是$historyRecord
?我尝试了这个,但是我有“PHP致命错误:达到了最大函数嵌套级别'1000',检测错误:在“$em->flush();”之前设置“$this->things=[];”非常重要。“对不起,我也遇到过这种情况!”!,更新我的答案,谢谢Igor。根据当前的:EntityManager\flush()
无法在postfush()中安全调用致命错误@IgorLadela:的可能解决方法。