php多维数组选择框mysql插入
我有以下html代码:php多维数组选择框mysql插入,php,Php,我有以下html代码: <select id="users_list" data-placeholder="Choose a user..." multiple name="users_list[]"> <?php while($users = mysql_fetch_array($all_users)){ ?> <option value='<?php echo serialize(arra
<select id="users_list" data-placeholder="Choose a user..." multiple name="users_list[]">
<?php while($users = mysql_fetch_array($all_users)){ ?>
<option value='<?php echo serialize(array($users['id_user'], $users['name'], $users['image_url'])); ?>' <?php if($users['id_user'] == $_SESSION['user_id']) echo "disabled"; ?>><?php echo $users['name']; ?></option>
<?php } ?>
</select>
这不对,我需要另外一个PHP代码来执行操作。请提供帮助。我会首先检查数据是否正确未序列化。。是的,它已正确序列化。)
serialize()
返回可能包含换行符和空字节等内容的二进制字符串。您不应该在HTML环境中更改输出。您最好将用户ID发送到
并检索数据服务器端的其余部分。您的INSERT
查询指定了八列,但只提供了六个值。是的,直到有人将无效的序列化数据发布到您的页面,此脚本才会失败。
$users_list = $_POST['users_list'];
foreach($users_list as $user)
{
$user = unserialize($user);
foreach($user as $info){
}
$query = "INSERT INTO messages (from_user, to_user, text, sender_name, sender_image, recipant_name, recipant_image, date) VALUES ('$uid', '$user', '$message', '$uname', '$uimage', '$time')";
$insert = mysql_query($query);
$mid = mysql_insert_id();
update_user_notf($user, $uid, $uname, $uimage, $mid, "message");
}