Php Foreach循环+；联合数组

如果我有以下代码：

$employeeAges;
$employeeAges["Lisa"] = "28";
$employeeAges["Jack"] = "16";
$employeeAges["Ryan"] = "35";
$employeeAges["Rachel"] = "46";
$employeeAges["Grace"] = "34";

foreach( $employeeAges as $name => $age){
    echo "Name: $name, Age: $age <br />";
}

如您所见，我只想获取specifics$key的$value。上面的代码输出以下错误：

Trying to get property of non-object 

---

有人能帮我处理这段代码吗？非常感谢。

如果我对你的理解是正确的，你只是想知道某个人的年龄，那么就这样做：

$selective = $employeeAges["Lisa"];
$secondary = $employeeAges["Grace"];
echo "The person you're looking for is $selective years old. And the other one is $secondary years old.";

->

运算符用于访问对象的命名成员。见：

如注释中所述，要遍历数组以查找特定键，请执行以下操作：

foreach ($employeeAges as $name => $age) {
    if ($name == "Grace") {
        echo $name . " is " . $age . " years old";
        break;
    }
}

---

所以你只想打印年龄

$employeeAges;
$employeeAges["Lisa"] = "28";
$employeeAges["Jack"] = "16";
$employeeAges["Ryan"] = "35";
$employeeAges["Rachel"] = "46";

$employeeAges[“Grace”]=“34”

使用这样的foreach循环只需将键强制输入到

$name

中，将值强制输入到

$age

中，而无需调用对象，因此会出现错误

---

不过，我认为@jli有一个更适合你的问题的答案。

我对这个问题的解释不同

<?php
//Assuming this is your array

$employeeAges["Lisa"] = "28";
$employeeAges["Jack"] = "16";
$employeeAges["Ryan"] = "35";
$employeeAges["Rachel"] = "46";
$employeeAges["Grace"] = "34";

echo $employeeAges["Lisa"]; //Will output 28
echo $employeeAges["Jack"]; //Will output 16
echo $employeeAges["Grace"]; //Will output 34

---

不好意思，谢谢！我刚才尝试使用for循环，而不是for-each。当它达到Grace并输出她的年龄时，是否可以进行“为”和“断”操作？当然可以，但它违背了关联数组的目的。我会更新我的答案的。很抱歉，花了这么长时间（在手机软键盘上打字…）没问题，很高兴我能帮上忙：D
foreach($employeeAges as $name=>$age) {
  echo $age;
}

<?php
//Assuming this is your array

$employeeAges["Lisa"] = "28";
$employeeAges["Jack"] = "16";
$employeeAges["Ryan"] = "35";
$employeeAges["Rachel"] = "46";
$employeeAges["Grace"] = "34";

echo $employeeAges["Lisa"]; //Will output 28
echo $employeeAges["Jack"]; //Will output 16
echo $employeeAges["Grace"]; //Will output 34