Php 将表单信息发送到电子邮件

Php 将表单信息发送到电子邮件,php,forms,email,submit,Php,Forms,Email,Submit,我有一个表单可以将信息发送到php文档。测试时,我提交并显示数组,但不会转到电子邮件地址 <?php require_once("/includes/fbcheader.php"); ?> <div class="comments"> <h3> We Welcome All Comments </h3> <form action="/php/contact-send.php" method="post"

我有一个表单可以将信息发送到php文档。测试时,我提交并显示数组,但不会转到电子邮件地址

<?php require_once("/includes/fbcheader.php"); 
?>
<div class="comments">
     <h3> We Welcome All Comments </h3>
   <form action="/php/contact-send.php" method="post" 
                                            id="contact-form" class="form">
     <p class="input-block"> 
          <label for="form-name" >Name</label>
          <input type="text" value name="name" id="form-name" 
               autofocus placeholder="Please enter name" required>
          </p>
        <p class="input-block">
            <label for="form-email" >Email</label>
            <input type="email" value name="email" id="form-email" 
                 required placeholder="Please enter E-Address">
            <input type="hidden" value name="age" id="age">
        </p>
        <p class="input-block">
            <label for="form-subject" >Subject</label>
            <input type="text" value name="subject" id="form-subject"
                 required placeholder="Please enter subject">
        </p>
        <p class="textarea-block">
            <label for="form-message">Comment</label>
            <textarea name="message" id="form-message" 
                 cols="70" rows="10"></textarea>
        </p>
   <div class="clear"></div>
                <input type="hidden" name="firstname" id="firstname">
                <input type="submit" value="Send" id="form-submit">
                <p class="hide" id="response"></p>
            <div class="hide">
                <label for="spam-check">Do not fill out this field</label>
                <input name="spam-check" type="text" value id="spam-check">
            </div>
    </form>
</div>
</body>
</html>

我们欢迎所有评论

名称

电子邮件

主题

评论

不要填写此字段
这是发送php执行代码的代码

<html>
<head>
 <title>Contact-Send</title>
</head>
 <body>
   <?php
      if(null!==($_POST["name"])) {
          $name = $_POST["name"];
         /* echo "Please enter 'Name'<br />"; */
      } else {
          $name = "";
      }
      if(null!==($email = $_POST["email"])) {
          $email = $_POST["email"];
          /* echo "Please enter 'E_Mail'<br />"; */
      } else {
          $email = "";
      }
      if(null!==($email = $_POST["subject"])) {
          $form_email = $_POST["subject"];
          /* echo "Please enter 'Subject'<br />"; */
      } else {
          $subject = "";
      }
    if(null!==($message = $_POST["message"])) {
        $message = $_POST["message"];
        /* echo "Please enter your message<br />"; */
    }   else {
        $message = "";
    }
    /*echo "{$name}, {$email}, {$message}";*/

  $email_from = '$Email';

  $email_subject = "New Form submission";

  $email_body = "You have received a new message from the user $name.\n".
                        "Here is the message:\n $message".

  $to = "me@myaddress.com";
   ?>
   <br>
     <?php
      $headers = "From: $email_from \r\n";

      $headers .= "Reply-To: $form_email \r\n";

    mail($to,$email_subject,$email_body,$headers);

    header("thank-you.html");
   ?>

   </body>
  </html>

联系发送


提交时,我只需获取显示输入字段内容的数组

快速查看您的PHP代码,我会看到以下内容:

这:
if(null!==($email=$\u POST[“email”])
将失败,因为您正在运行一个无任何内容的检查。它应该是:
if(null!==($\u POST[“email”])

这里有一个未定义的变量:
$email\u from='$email'这将只输出“$Email”。它应该是
$email\u from=$email(根据您的代码)。然而,你只是在这里重新分配变量,你根本不需要这样做

您的
$email\u body
$to
地址


您可以使用
标题(“thank-You.html”)将失败,因为根据您的代码,输出已在此处开始
您的意思是“我只需获取显示输入字段内容的数组”?请检查
mail()
函数的返回值,您的
From
标题将导致消息失败,您需要在此处使用双引号。实际上根本没有…
值名称
,这将导致一些意外的结果。@johncode-当我按submit时,下一页显示输入名称和其中的内容。例如数组([name]=>Jonathan;[email]=>JonDoe@abcsite.com;[年龄]=>;[主题]=>test;…那么你的
没有价值,也没有参考,所以我不知道你为什么要使用它,对于
,还有我已经说过的
value name
。谢谢@M.Doye,谢谢你花时间和考虑。在清理了一些明显的错误并采纳了你上面的建议之后,我已经把代码准备好了rk.还有一些关于输出格式的问题:即设置字体标签()。我知道我将不得不退出php,但只是想知道语法可能是什么。再次感谢。@JZeig1没问题,很高兴能提供帮助。您可以找到一个非常好的示例来说明如何进行此操作。这是一个非常好的示例,非常简单,您不必对代码进行太多更改:-)
<?php
      if(null!==($_POST["name"])) {
          $name = $_POST["name"];
         /* echo "Please enter 'Name'<br />"; */
      } else {
          $name = "";
      }
      if(null!==($_POST["email"])) {
          $email = $_POST["email"];
          /* echo "Please enter 'E_Mail'<br />"; */
      } else {
          $email = "";
      }
      if(null!==($_POST["subject"])) {
          $form_email = $_POST["subject"];
          /* echo "Please enter 'Subject'<br />"; */
      } else {
          $subject = "";
      }
    if(null!==($_POST["message"])) {
        $message = $_POST["message"];
        /* echo "Please enter your message<br />"; */
    }   else {
        $message = "";
    }
    /*echo "{$name}, {$email}, {$message}";*/

  $email_subject = "New Form submission";

  $email_body = "You have received a new message from the user $name.\n".
                "Here is the message:\n $message";

  $to = "me@myaddress.com";
    $headers = "From: $email \r\n";
    $headers .= "Reply-To: $email \r\n";
    mail($to,$email_subject,$email_body,$headers);
    header("Location: thank-you.html");
   ?>