在php和mysqli中没有搜索结果
我不明白为什么我在这段代码中没有得到任何结果,每次我运行它,else语句都会运行在php和mysqli中没有搜索结果,php,search,mysqli,Php,Search,Mysqli,我不明白为什么我在这段代码中没有得到任何结果,每次我运行它,else语句都会运行 <?php if(isset($_POST['search'])){ $search = mysqli_real_escape_string($connection, $_POST['user_query']); $sql = "SELECT * FROM search WHERE search_title LIKE
<?php
if(isset($_POST['search'])){
$search = mysqli_real_escape_string($connection, $_POST['user_query']);
$sql = "SELECT * FROM search WHERE search_title LIKE '%user_query%' OR search_desc LIKE '%user_query%' OR search_key LIKE '%user_query%' ";
$run = mysqli_query($connection, $sql);
$queryResult = mysqli_num_rows($run);
if($queryResult > 0){
while($rel_rows = mysqli_fetch_assoc($queryResult)){
echo "<div id='post'>
<a href='#'><img src='$rel_rows[search_img]'></a>
<a href='#'><h4 class='post_name'>$rel_rows[search_title]</h4></a>
<p class='post_info'> $rel_rows[search_desc]</p>
</div>";
}
}
else{
echo "There are no results for your search";
}
}
?>
您传递了错误的搜索字符串
改为:
$sql = "SELECT * FROM search WHERE search_title LIKE '%$search%' OR search_desc LIKE '%$search%' OR search_key LIKE '%$search%' ";
mysqli_fetch_assoc($run)
您在mysqli_fetch_assoc(..)中作为参数传递了错误的变量
改为:
$sql = "SELECT * FROM search WHERE search_title LIKE '%$search%' OR search_desc LIKE '%$search%' OR search_key LIKE '%$search%' ";
mysqli_fetch_assoc($run)
试试这个
<?php
if(isset($_POST['search'])){
$search = mysqli_real_escape_string($connection, $_POST['user_query']);
$user_query=$search;
//Added this line and replace user_query to $user_query in SQL query statement
$sql = "SELECT * FROM search WHERE search_title LIKE '%$user_query%' OR search_desc LIKE '%$user_query%' OR search_key LIKE '%$user_query%' ";
$run = mysqli_query($connection, $sql);
$queryResult = mysqli_num_rows($run);
if($queryResult > 0){
while($rel_rows = mysqli_fetch_assoc($run)){
echo "<div id='post'>
<a href='#'><img src='$rel_rows[search_img]'></a>
<a href='#'><h4 class='post_name'>$rel_rows[search_title]</h4></a>
<p class='post_info'> $rel_rows[search_desc]</p>
</div>";
}
}
else{
echo "There are no results for your search";
}
}
?>
未定义用户查询
。使用全文索引会更好。您还应该参数化查询。它实际上是在您的字符串中搜索文本user\u query
,因为它是硬编码的。对您所做的以及如何解决OP的问题进行一些解释将非常有用。非常感谢!!