Php SQL高分

好的，我有两个MYSQL表：

CREATE TABLE `sessions` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `userID` int(11) NOT NULL,
  `runTime` int(11) NOT NULL,
  `monstersKilled` int(11) NOT NULL,
  `profit` int(11) NOT NULL,
  `tasks` int(11) NOT NULL,
  `xpGain` int(11) NOT NULL,
  `lastupdate` int(11) NOT NULL,
  PRIMARY KEY (`id`)
);

以及

正如您所看到的，sessions有一个指向用户ID的链接。现在我想创建一个总分很高的PHP文件，但由于我对PHP和MYSQL的了解很少，我不知道如何开始。总高分将按总运行时间排序

例如： 在用户中，我有用户1（cody）和用户2（Joe）。现在，在会话中，我有3个会话：

id, userID, runTime, monstersKilled, profit, tasks, xpGain, lastupdate
12, 1, 27, 14, 6200, 0, 5050, 1282325410
19, 1, 18, 1, 277, 1, 168, 1278897756
1968, 2, 195, 433, 111345, 4, 73606, 1280993244

打印输出应符合以下要求：

Place, username, Total Run Time, Total Monsters Killed, Total profit, Total tasks, Total Exp Gain
1. Joe, 195, 433,11345,4,73606
2. Cody, 55, 15, 1, 5218

使用：

---

这个脚本应该在一个整洁的表格中为您输出高分。感谢用于SQL查询的OMG小马

<?php
$dbhost = 'localhost';  // Database Host
$dbuser = 'user';       // Database User
$dbpass = 'password';   // Database Password
$dbname = 'database';   // Database Name

$db = mysql_connect($dbhost, $dbuser, $dbpass);
mysql_select_db($dbname, $db);

$limit = 10; // The number of users to show in the top highscores.  Set to 0 to show all

$sql = 'SELECT u.user,
         SUM(s.runtime) AS total_run_time,
         SUM(s.monsterskilled) AS total_monsters_killed,
         SUM(s.profit) AS total_profit,
         SUM(s.tasks) AS total_tasks, 
         SUM(s.xpgain) AS total_xp_gained
        FROM USERS u
        JOIN SESSION s ON s.userid = u.userid
        GROUP BY u.user
        ORDER BY total_run_time DESC';

if ($limit > 0) {
    $sql .= ' LIMIT '.$limit;
}

$get_scores = mysql_query($sql);
$scores = array();

$rank = 0;
while($score = mysql_fetch_array($get_scores)) {
    ++$rank;
    $scores[] = '<td>'.$rank.'</td><td>'.$score['user'].'</td><td>'.$score['total_run_time'].'</td><td>'.$score['total_monsters_killed'].'</td><td>'.$score['total_profit'].'</td><td>'.$score['total_tasks'].'</td><td>'.$score['total_xp_gained'].'</td>';
}

echo '<table><tbody>';
echo '<tr><td>Place</td><td>Username</td><td>Total Run Time</td><td>Total Monsters Killed, Total profit</td><td>Total tasks</td><td>Total Exp Gain</td></tr><tr>';
echo implode('</tr><tr>', $scores);
echo '</tr></tbody></table>';
?>

回答得很好，我不太使用MySQL，所以不知道它是否支持行范围，但您可能希望有一个SELECT TOP n或SELECT range，因为对于许多用户，此查询很容易变得非常慢。@Tom Gullen:MySQL的

LIMIT

语法相当于SQL Server的

TOP

，实际上，比你考虑<代码>偏移< /代码>参数时更好。谢谢简化我的答案：

  SELECT u.user,
         SUM(s.runtime) AS total_run_time,
         SUM(s.monsterskilled) AS total_monsters_killed,
         SUM(s.profit) AS total_profit,
         SUM(s.tasks) AS total_tasks, 
         SUM(s.xpgain) AS total_xp_gained
    FROM USERS u
    JOIN SESSION s ON s.userid = u.userid
GROUP BY u.user
ORDER BY total_run_time DESC

<?php
$dbhost = 'localhost';  // Database Host
$dbuser = 'user';       // Database User
$dbpass = 'password';   // Database Password
$dbname = 'database';   // Database Name

$db = mysql_connect($dbhost, $dbuser, $dbpass);
mysql_select_db($dbname, $db);

$limit = 10; // The number of users to show in the top highscores.  Set to 0 to show all

$sql = 'SELECT u.user,
         SUM(s.runtime) AS total_run_time,
         SUM(s.monsterskilled) AS total_monsters_killed,
         SUM(s.profit) AS total_profit,
         SUM(s.tasks) AS total_tasks, 
         SUM(s.xpgain) AS total_xp_gained
        FROM USERS u
        JOIN SESSION s ON s.userid = u.userid
        GROUP BY u.user
        ORDER BY total_run_time DESC';

if ($limit > 0) {
    $sql .= ' LIMIT '.$limit;
}

$get_scores = mysql_query($sql);
$scores = array();

$rank = 0;
while($score = mysql_fetch_array($get_scores)) {
    ++$rank;
    $scores[] = '<td>'.$rank.'</td><td>'.$score['user'].'</td><td>'.$score['total_run_time'].'</td><td>'.$score['total_monsters_killed'].'</td><td>'.$score['total_profit'].'</td><td>'.$score['total_tasks'].'</td><td>'.$score['total_xp_gained'].'</td>';
}

echo '<table><tbody>';
echo '<tr><td>Place</td><td>Username</td><td>Total Run Time</td><td>Total Monsters Killed, Total profit</td><td>Total tasks</td><td>Total Exp Gain</td></tr><tr>';
echo implode('</tr><tr>', $scores);
echo '</tr></tbody></table>';
?>