Php 替换数组中的值不'；行不通

我快发疯了，花了几个小时在数组中尝试替换值的不同方法，但我无法让它工作

foreach($potentialMatches as $potentialKey)
{
  $searchKeywordQuery = "SELECT keyword, id FROM picture WHERE id='$potentialKey'";
  $searchKeywords = mysql_query($searchKeywordQuery) or die(mysql_error());
  while ($searchKeyWordsRow = mysql_fetch_array($searchKeywords))
  {
    $keyword = $searchKeyWordsRow['keyword'];
    $pictureKeywordArray[$searchKeyWordsRow['id']]['keywords'] = explode(",", $keyword);
    $pictureKeywordArray[$searchKeyWordsRow['id']]['match'] = 4;
  }
}
foreach($pictureKeywordArray as $key = > $picValue)
{
  foreach($picValue['keywords'] as $key = > $picIdValue)
  {
    if ($picIdValue == $searchIdKey)
    {
      echo $picValue['match'];
      $picValue['match']++;
      echo $picValue['match'];
    }
  }
}
foreach($pictureKeywordArray as $key = > $picValue)
{
  echo $picValue['match'];
}

---

正如您所看到的，我是新手，当我在foreach循环中回显picValue['match']时，它会在“++”之后给我一个正确的值。但在下面，当我再次调用数组时，它给出的值是4，而不是预期的5。提前感谢您的帮助。

在这一秒中，您需要通过引用调用它：

foreach($pictureKeywordArray as $key => &$picValue) 
{                                       //^-- `&` makes it by reference
  foreach($picValue['keywords'] as $key => $picIdValue)
  {
    if ($picIdValue == $searchIdKey)
    {
      echo $picValue['match'];
      $picValue['match']++; //now updates what you want it to update
      echo $picValue['match'];
    }
  }
}

---

foreach

处理数据的副本。必须使用引用来修改原始文件：

foreach ($foo as $i => &$f)
{
  $f++;
}

unset($f); // important to do this if you ever want to reuse that variable later 

---

因为您在第一种情况下使用项目副本，请尝试使用

$pictureKeywordArray[$key]['match']

而不是

$picValue['match']

+1。这（使用密钥）通常是最干净的解决方案。引用可能会变得混乱。在这个变量中，$key被覆盖（因为在两个foreach中都使用了），我们应该小心这个。。。