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PHP帖子不使用twitter api_Php_Twitter_Oauth - Fatal编程技术网

PHP帖子不使用twitter api

PHP帖子不使用twitter api,php,twitter,oauth,Php,Twitter,Oauth,我正在尝试使用以下PHP向我的帐户添加收藏夹: <?php if(isset($_POST['submit'])) { $fav = $_REQUEST['fav']; $connection->post('favorites/create', array('id' => $fav)); echo "<div style='padding-bottom: 5px; color: #0099FF;'>Fav Created Succes

我正在尝试使用以下PHP向我的帐户添加收藏夹:

<?php
    if(isset($_POST['submit'])) {
    $fav = $_REQUEST['fav'];
    $connection->post('favorites/create', array('id' => $fav));
    echo "<div style='padding-bottom: 5px; color: #0099FF;'>Fav Created Successfully.</div>";

    }
?>
$favorite = $connection->post('favorites/create/'.$id);

当我尝试它时,它说了以下内容

此方法需要GET

尽管twitterapi文档说它需要一篇帖子。因此,尝试对其执行
GET
请求:

 $response = $connection->get('favorites/create', array('id' => $fav));
 // now print the response to see if any error pops up:
 print_r($response);

如果我没弄错的话,您不需要添加“id”参数

查看URL以创建收藏夹,其中“12345”是tweet的ID

$response = $connection->post('favorites/create/'.$fav);

ID不是参数。

我正在尝试使用以下PHP向我的帐户添加收藏夹:

<?php
    if(isset($_POST['submit'])) {
    $fav = $_REQUEST['fav'];
    $connection->post('favorites/create', array('id' => $fav));
    echo "<div style='padding-bottom: 5px; color: #0099FF;'>Fav Created Successfully.</div>";

    }
?>
$favorite = $connection->post('favorites/create/'.$id);

其中,
$id
是状态id,但favorite不返回任何内容

这是使用Oauth,$connection是令牌。当您使用POST时,使用
打印($response)
会出现什么错误?他是通过
数组('id'=>$fav)
来实现的。