Php 比较两个多维数组,然后仅创建唯一的
我已经试了好几个小时了 我有两个多维数组Php 比较两个多维数组,然后仅创建唯一的,php,arrays,multidimensional-array,unique,Php,Arrays,Multidimensional Array,Unique,我已经试了好几个小时了 我有两个多维数组 $newData ( [0] => Array( [id] => 1 [name] => John [sex] => male ) [1] => Array( [id] => 2 [name] => Kenny [sex] => male ) [2] => A
$newData (
[0] => Array(
[id] => 1
[name] => John
[sex] => male
)
[1] => Array(
[id] => 2
[name] => Kenny
[sex] => male
)
[2] => Array(
[id] => 3
[name] => Sarah
[sex] => female
)
[3] => Array(
[id] => 4
[name] => George
[sex] => male
)
)
$oldData (
[0] => Array(
[id] => 3
[name] => Sarah
[sex] => female
)
[1] => Array(
[id] => 4
[name] => George
[sex] => male
)
[2] => Array(
[id] => 5
[name] => Peter
[sex] => male
)
[3] => Array(
[id] => 6
[name] => Lexi
[sex] => female
)
)
我需要比较$newData和$oldData,只获取第一个公共数组之前的新数据
我的$newData将是:
$newData (
[0] => Array(
[id] => 1
[name] => John
[sex] => male
)
[1] => Array(
[id] => 2
[name] => Kenny
[sex] => male
)
)
我尝试了从array_unique(如果比较ID键)到array_unique的所有方法,但没有任何方法可以正常工作
我需要先合并它们吗?地图?呸,我不知道,我太迷路了
任何帮助都会很棒我只会做一个嵌套的foreach循环。我不知道您使用的是哪种编程语言,但假设它是PHP($):
$tmpArray=array();
foreach($newData作为$data1){
$duplicate=false;
foreach($oldData作为$data2){
如果($data1['id']===$data2['id']&&$data1['name']==$data2['name']&&$data1['sex']===$data2['sex']),则$duplicate=true;
}
如果($duplicate==false)$tmpArray[]=$data1;
}
然后在
$tmpArray
变量中有所需的数组。当然,您可以将$newData=$tmpArray代码>之后。只需在$newData
上迭代,直到从$oldData
中找到第一个元素
$cmp = $oldData[0];
$data = array();
foreach ($newData as $el) {
if ($el['id'] === $cmp['id']
&& $el['name'] === $cmp['name']
&& $el['sex'] === $cmp['sex'])
break;
$data[] = $el;
}
您的新数据将存储在$data
中,使用它怎么样?通过修改答案
如果存在重复项,则取消设置动态键
public function removeDuplicate($oldData, $newData, $key)
{
$tmpArray = array();
foreach ($newData as $data1) {
$duplicate = false;
foreach ($oldData as $data2k => $data2v) {
if ($data1[$key] === $data2v[$key]) {
unset($newData[$data2k]);
$duplicate = true;
}
}
if ($duplicate === true) {
$tmpArray[] = $data1;
} else {
$tmpArray[] = $data1;
}
}
return $tmpArray;
}
然后你只要打个电话
removeDuplicate($oldData, $newData, 'name');//or whatever you want
通过复制您的代码,然后将密钥名称更改为我当前拥有的名称,当我打印\r$tmparray时,它将返回一个空数组。显然,您键入了错误的内容。如果我在这里尝试这段代码,我会得到你想要的数组…我可能会,但我只是重新构建了代码,这样我更容易阅读。不管怎样,它是有效的,而你刚刚救了我,使我免于拔出所有的头发。我想得太多了。