Php AJAX表单重新加载我的页面:(
我有一个ajax表单,它从我的表单submit中读取数据 我希望在提交表单时,它会显示来自php回调的响应。例如,如果用户输入了密码,则更新表并返回类似于Php AJAX表单重新加载我的页面:(,php,ajax,Php,Ajax,我有一个ajax表单,它从我的表单submit中读取数据 我希望在提交表单时,它会显示来自php回调的响应。例如,如果用户输入了密码,则更新表并返回类似于echo“成功更新密码”的内容; 我曾尝试阅读不同的帖子/博客,了解如何做到这一点,但我的错误不断发生。当我输入密码或个人资料图片后单击“保存”按钮时,它会不断刷新页面 我的HTML表单代码: <div class="modal fade -dark" id="ben2" data-animate-show="fadeInRight" d
echo“成功更新密码”的内容;
我曾尝试阅读不同的帖子/博客,了解如何做到这一点,但我的错误不断发生。当我输入密码或个人资料图片后单击“保存”按钮时,它会不断刷新页面
我的HTML表单代码:
<div class="modal fade -dark" id="ben2" data-animate-show="fadeInRight" data-animate-hide="fadeOutRight">
<div class="modal-dialog">
<div class="modal-content -padded">
<div class="modal-body _text-center">
<form class="form-horizontal" enctype="multipart/form-data" id="myAccount" method="post" action="">
<div class="form-group">
<label class="col-md-12 control-label" style="color: white; opacity: 100%;">Username</label>
<div class="col-md-12">
<input type="text" class="form-control" value="<?php foreach($users as $user) { echo $user[1]; } ?>" disabled>
</div>
</div>
<div class="form-group">
<label class="col-md-12 control-label" for="example-email" style="color: white; opacity: 100%;">Email</label>
<div class="col-md-12">
<input type="email" id="example-email" name="example-email" class="form-control" value="<?php foreach($users as $user) { echo $user[3]; } ?>" disabled>
</div>
</div>
<div class="form-group">
<label class="col-md-12 control-label" style="color: white; opacity: 100%;">New Password</label>
<div class="col-md-12">
<input type="password" class="form-control default my-password required" name="securePassword_Val" id="form-element-colors-info" placeholder="Enter your new password here">
</div>
</div>
<div class="form-group">
<label class="col-md-12 control-label" style="color: white; opacity: 100%;">Profile Pic</label>
<div class="col-md-12">
<input class="form-control default profile-pic required" type="file" name="fileToUpload" id="form-elements-file">
</div>
</div>
<div class="form-group">
<label class="col-md-12 control-label" style="color: white; opacity: 100%;">User Level</label>
<div class="col-md-12">
<input type="text" class="form-control" value="<?php echo $member_config->userLevelValidation($con); ?>" disabled>
</div>
</div>
</div>
<div class="col-sm-12">
<div class="modal-footer _text-center _margin-bottom-none">
<div class="btn-group">
<button class="btn -dark" data-dismiss="modal" aria-hidden="true" title="Close Without saving changes"><i class="fa fa-times"></i></button>
<button class="btn -dark" type="submit" name="SaveUserChanges" title="Save changes to your account"><i class="fa fa-save"></i></button>
</div>
</div>
</form>
<div id="myAccountResponse"></div>
</div>
</div>
</div>
<script>
//JQuery Script to submit Form
$(document).ready(function () {
$("#myAccount").validate({
submitHandler : function () {
// your function if, validate is success
$.ajax({
type : "POST",
url : "includes/form_submit.php",
data : $('#myAccount').serialize(),
success : function (data) {
$('#myAccountResponse').html(data);
}
console.log('AJAX ERROR');
});
}
});
});
</script>
//Upload users image to our /uploads directory
$uploaddir = 'uploads/';
$uploadfile = $uploaddir . basename($_FILES['fileToUpload']['name']);
$save_to_database = ("uploads/" . $_FILES["fileToUpload"]["name"]);
$normalPassword = mysqli_real_escape_string($con, $_POST["securePassword_Val"]);
$pwd = password_hash($normalPassword, PASSWORD_DEFAULT);
$username = $_SESSION["username"];
//Run a list of checks so they don't have to type in a value if they don't want to change a current certain value
if(isset($_POST['fileToUpload']) & isset($_POST['securePassword_Val'])) {
if(move_uploaded_file($_FILES['fileToUpload']['tmp_name'], $uploadfile)) { echo 'Successfully uploaded image'; } else { die('Could not upload file.<br>Contact the Administrator of the website for more infomration.'); }
$query = "UPDATE users SET password = '$pwd', profile_picture = '$save_to_database' WHERE username='$username'";
$success['updatedAll'] = 'Successfully updated your password and profile picture!';
}
else if (empty($_POST['fileToUpload']) & !empty($_POST['securePassword_Val'])) {
$query = "UPDATE users SET password = '$pwd' WHERE username='$username'";
$success['updatedPwd'] = 'Successfully updated your password!';
}
else if (empty($_POST['securePassword_Val']) & !(empty($_POST['fileToUpload']))) {
if(move_uploaded_file($_FILES['fileToUpload']['tmp_name'], $uploadfile)) { echo 'Successfully uploaded image'; } else { die('Could not upload file.<br>Contact the Administrator of the website for more infomration.'); }
$query = "UPDATE users SET profile_picture = '$save_to_database' WHERE username='$username'";
$success['updatedPpic'] = 'Successfully updated your profile picture!';
}
else if (empty($_POST['securePassword_Val']) & empty($_POST['fileToUpload'])) {
$errors['etyBoth'] = 'You must enter a value to change!';
}
if(count($errors) > 0) {
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
echo $errors;
exit;
}
} else {
//Write our success return here
echo $success;
$result = mysqli_query($con, $query) or die('error');
}
我的表单提交.php代码:
<div class="modal fade -dark" id="ben2" data-animate-show="fadeInRight" data-animate-hide="fadeOutRight">
<div class="modal-dialog">
<div class="modal-content -padded">
<div class="modal-body _text-center">
<form class="form-horizontal" enctype="multipart/form-data" id="myAccount" method="post" action="">
<div class="form-group">
<label class="col-md-12 control-label" style="color: white; opacity: 100%;">Username</label>
<div class="col-md-12">
<input type="text" class="form-control" value="<?php foreach($users as $user) { echo $user[1]; } ?>" disabled>
</div>
</div>
<div class="form-group">
<label class="col-md-12 control-label" for="example-email" style="color: white; opacity: 100%;">Email</label>
<div class="col-md-12">
<input type="email" id="example-email" name="example-email" class="form-control" value="<?php foreach($users as $user) { echo $user[3]; } ?>" disabled>
</div>
</div>
<div class="form-group">
<label class="col-md-12 control-label" style="color: white; opacity: 100%;">New Password</label>
<div class="col-md-12">
<input type="password" class="form-control default my-password required" name="securePassword_Val" id="form-element-colors-info" placeholder="Enter your new password here">
</div>
</div>
<div class="form-group">
<label class="col-md-12 control-label" style="color: white; opacity: 100%;">Profile Pic</label>
<div class="col-md-12">
<input class="form-control default profile-pic required" type="file" name="fileToUpload" id="form-elements-file">
</div>
</div>
<div class="form-group">
<label class="col-md-12 control-label" style="color: white; opacity: 100%;">User Level</label>
<div class="col-md-12">
<input type="text" class="form-control" value="<?php echo $member_config->userLevelValidation($con); ?>" disabled>
</div>
</div>
</div>
<div class="col-sm-12">
<div class="modal-footer _text-center _margin-bottom-none">
<div class="btn-group">
<button class="btn -dark" data-dismiss="modal" aria-hidden="true" title="Close Without saving changes"><i class="fa fa-times"></i></button>
<button class="btn -dark" type="submit" name="SaveUserChanges" title="Save changes to your account"><i class="fa fa-save"></i></button>
</div>
</div>
</form>
<div id="myAccountResponse"></div>
</div>
</div>
</div>
<script>
//JQuery Script to submit Form
$(document).ready(function () {
$("#myAccount").validate({
submitHandler : function () {
// your function if, validate is success
$.ajax({
type : "POST",
url : "includes/form_submit.php",
data : $('#myAccount').serialize(),
success : function (data) {
$('#myAccountResponse').html(data);
}
console.log('AJAX ERROR');
});
}
});
});
</script>
//Upload users image to our /uploads directory
$uploaddir = 'uploads/';
$uploadfile = $uploaddir . basename($_FILES['fileToUpload']['name']);
$save_to_database = ("uploads/" . $_FILES["fileToUpload"]["name"]);
$normalPassword = mysqli_real_escape_string($con, $_POST["securePassword_Val"]);
$pwd = password_hash($normalPassword, PASSWORD_DEFAULT);
$username = $_SESSION["username"];
//Run a list of checks so they don't have to type in a value if they don't want to change a current certain value
if(isset($_POST['fileToUpload']) & isset($_POST['securePassword_Val'])) {
if(move_uploaded_file($_FILES['fileToUpload']['tmp_name'], $uploadfile)) { echo 'Successfully uploaded image'; } else { die('Could not upload file.<br>Contact the Administrator of the website for more infomration.'); }
$query = "UPDATE users SET password = '$pwd', profile_picture = '$save_to_database' WHERE username='$username'";
$success['updatedAll'] = 'Successfully updated your password and profile picture!';
}
else if (empty($_POST['fileToUpload']) & !empty($_POST['securePassword_Val'])) {
$query = "UPDATE users SET password = '$pwd' WHERE username='$username'";
$success['updatedPwd'] = 'Successfully updated your password!';
}
else if (empty($_POST['securePassword_Val']) & !(empty($_POST['fileToUpload']))) {
if(move_uploaded_file($_FILES['fileToUpload']['tmp_name'], $uploadfile)) { echo 'Successfully uploaded image'; } else { die('Could not upload file.<br>Contact the Administrator of the website for more infomration.'); }
$query = "UPDATE users SET profile_picture = '$save_to_database' WHERE username='$username'";
$success['updatedPpic'] = 'Successfully updated your profile picture!';
}
else if (empty($_POST['securePassword_Val']) & empty($_POST['fileToUpload'])) {
$errors['etyBoth'] = 'You must enter a value to change!';
}
if(count($errors) > 0) {
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
echo $errors;
exit;
}
} else {
//Write our success return here
echo $success;
$result = mysqli_query($con, $query) or die('error');
}
//将用户图像上载到我们的/uploads目录
$uploaddir='uploads/';
$uploadfile=$uploaddir.basename($_FILES['fileToUpload']['name']);
$save_to_database=(“uploads/”$_FILES[“fileToUpload”][“name”]);
$normalPassword=mysqli\u real\u escape\u字符串($con,$\u POST[“securePassword\u Val]”);
$pwd=密码\u散列($normalPassword,密码\u默认值);
$username=$\会话[“username”];
//运行检查列表,这样如果他们不想更改当前的某个值,就不必键入值
如果(isset($\u POST['fileToUpload'])和isset($\u POST['securePassword\u Val'])){
如果(move_upload_file($_FILES['fileToUpload']['tmp_name'],$uploadfile)){echo'成功上载图像';}其他{die('无法上载文件。
请与网站管理员联系以获取更多信息。');}
$query=“更新用户设置密码='$pwd',配置文件\u图片='$save\u to_database',其中username='$username';
$success['updatedAll']=“成功更新了您的密码和个人资料图片!”;
}
else if(空($\u POST['fileToUpload'])和!空($\u POST['securePassword\u Val'])){
$query=“updateusers SET password='$pwd',其中username='$username';
$success['updatedPwd']=“成功更新了密码!”;
}
else if(空($\u POST['securePassword\u Val'])和!(空($\u POST['fileToUpload'])){
如果(move_upload_file($_FILES['fileToUpload']['tmp_name'],$uploadfile)){echo'成功上载图像';}其他{die('无法上载文件。
请与网站管理员联系以获取更多信息。');}
$query=“更新用户设置配置文件\u图片=”$save\u to_database”,其中username=“$username'”;
$success['updatedPpic']=“成功更新了您的个人资料图片!”;
}
else if(空($\u POST['securePassword\u Val'])和空($\u POST['fileToUpload'])){
$errors['ETYEATH']='必须输入一个值才能更改!';
}
如果(计数($errors)>0){
如果(!empty($_SERVER['HTTP_X_REQUESTED_WITH'])和&strtolower($_SERVER['HTTP_X_REQUESTED_WITH'])='xmlhttprequest'){
回音$错误;
出口
}
}否则{
//在这里写下我们的成功回报
成功的回声;
$result=mysqli_query($con,$query)或die('error');
}
您应该防止默认表单处理,例如:
<script>
//JQuery Script to submit Form
$(document).ready(function () {
$("#myAccount").validate({
submitHandler : function () {
// your code
return false; // Prevent default form handling
}
});
});
</script>
//提交表单的JQuery脚本
$(文档).ready(函数(){
$(“#我的帐户”)。验证({
submitHandler:函数(){
//你的代码
返回false;//防止默认表单处理
}
});
});
我认为您需要将return false;
放在submitHandler的末尾,告诉它不要进行正常的回发:
submitHandler : function () {
// your function if, validate is success
$.ajax({
type : "POST",
url : "includes/form_submit.php",
data : $('#myAccount').serialize(),
success : function (data) {
$('#myAccountResponse').html(data);
}
});
return false; //prevent default postback
}
另外,
console.log('AJAX ERROR');
位于错误的位置,如果检查控制台,可能会导致语法错误。如果要检查AJAX错误,请包含“ERROR”根据jQuery文档的回调选项。为了防止页面刷新,您可以将事件处理程序附加到submit按钮的onclick事件。应该给按钮一个id,并且它的类型应该从“submit”更改为“button”任何控制台错误?脚本是否正确加载并且在加载文档之前加载?我得到了答案jQuery.Deferred异常:$(…)。验证不是函数类型错误:$(…).validate不是一个函数
,它只是意味着您在使用时没有加载验证插件。好的,但是使用
或
?我认为您必须使用第二个函数,否则jQuery validate不会知道您已提交表单。a type=“button”按钮不会导致验证程序正在等待的表单提交事件。请检查浏览器控制台是否存在任何其他错误。如果您有脚本错误,则不会运行任何验证或ajax。我正在获取jQuery。延迟异常:$(…)。验证不是函数类型错误:$(…).validate不是一个函数
听起来好像你没有在你的页面中包含jquery验证插件文件。你应该有一个不,我知道为什么。这是因为我在我的主题中加载了另一个js文件,导致它没有在默认的jquery库中加载AJAX。我想我不能再在这个主题中使用AJAX了。