PHP合并数组并添加值

我需要帮助合并两个PHP数组：

阵列1：

Array
(
[0] => 2
[1] => 3
[2] => 4
[3] => 6
)

阵列2：

Array
(
[0] => Array
    (
        [id_sabor] => 2
        [chocolate] => N
    )

[1] => Array
    (
        [id_sabor] => 3
        [chocolate] => S
    )

[2] => Array
    (
        [id_sabor] => 4
        [chocolate] => N
    )

[3] => Array
    (
        [id_sabor] => 5
        [chocolate] => S
    )

[4] => Array
    (
        [id_sabor] => 6
        [chocolate] => N
    )

)

---

数组1上的值是活动对象。我需要在数组2或新数组中只保留那些与数组1中的

[id\u sabor]

匹配的数组（在本例中：

2、3、4

和

6

）。另外，在那些

[chocolate]=S

的数组上添加一个新值：

[costo_extra]=25

一种方法是使用并检查第一个数组是否包含

id\u sabor

的值

$array1 = [2, 3, 4, 6];
$array2 = [
    ["id_sabor" => 1, "chocolate" => "N"],
    ["id_sabor" => 2, "chocolate" => "N"],
    ["id_sabor" => 3, "chocolate" => "S"],
    ["id_sabor" => 4, "chocolate" => "N"],
    ["id_sabor" => 5, "chocolate" => "S"],
    ["id_sabor" => 6, "chocolate" => "N"]
];

$array2 = array_reduce($array2, function($carry, $item) use ($array1){
    if (in_array($item["id_sabor"], $array1)) {
        if ($item["chocolate"] === "S") {
            $item["costo_extra"] = 25;
        }
        $carry[] = $item;
    }
    return $carry;
});

---

只需在数组2上循环一次，如果s，则循环一些。您想创建什么？第二个数组包含数字和巧克力字母。预期的输出应该是多少？非常感谢，第四只鸟。这正是我需要的：）