Php 若否,;否则,如果在Codeigniter中
请检查我的脚本Php 若否,;否则,如果在Codeigniter中,php,codeigniter,Php,Codeigniter,请检查我的脚本 if($namachief != NULL) { echo $namachief; } else if ($namarm != NULL) { echo $namarm; } else { echo "Something wrong. Please contact US"; } 在这种情况下,我的条件
if($namachief != NULL)
{
echo $namachief;
}
else if ($namarm != NULL)
{
echo $namarm;
}
else
{
echo "Something wrong. Please contact US";
}
在这种情况下,我的条件不起作用=>$namarm!=NULL,我只得到白色页面,但在这种情况下它是正常的=>$namachief!=空
我这样做没关系
echo$namachief代码>&echo$namarm代码>
if () {
}
else if (){
}
else if(){
------------------------ My Script Here -----------------------------
}
下面的两个答案都是正确的。我的问题就在这里。以我的形式,我做到了这一点
None
然后我将其更改为None
将您的情况写如下:-
if(isset($namachief) && !empty($namachief)){
echo $namachief;
}
else if (isset($namarm) && !empty($namarm)){
echo $namarm;
}
else{
echo "Something wrong. Please contact US";
}
如果要打印两个变量,如果两个变量都已设置且具有有效值,则
if(empty($namarm) && empty($namachief)){
echo "Something wrong. Please contact US";
}
else if (!empty($namachief) && !empty($namarm)){
echo $namarm;
echo $namachief;
}
else if (isset($namarm) && !empty($namarm)){
echo $namarm;
}
else if(isset($namachief) && !empty($namachief)){
echo $namachief;
}
else{
// else stuff
}
将您的情况写在下面:-
if(isset($namachief) && !empty($namachief)){
echo $namachief;
}
else if (isset($namarm) && !empty($namarm)){
echo $namarm;
}
else{
echo "Something wrong. Please contact US";
}
如果要打印两个变量,如果两个变量都已设置且具有有效值,则
if(empty($namarm) && empty($namachief)){
echo "Something wrong. Please contact US";
}
else if (!empty($namachief) && !empty($namarm)){
echo $namarm;
echo $namachief;
}
else if (isset($namarm) && !empty($namarm)){
echo $namarm;
}
else if(isset($namachief) && !empty($namachief)){
echo $namachief;
}
else{
// else stuff
}
你试着这样做
if($namachief != NULL || $namachief != "")
{
echo $namachief;
}
else if ($namarm != NULL || $namarm != "")
{
echo $namarm;
}
else
{
echo "Something wrong. Please contact US";
}
你试着这样做
if($namachief != NULL || $namachief != "")
{
echo $namachief;
}
else if ($namarm != NULL || $namarm != "")
{
echo $namarm;
}
else
{
echo "Something wrong. Please contact US";
}
试着用if(!empty($namachief)){}我这样做了,结果与if(!empty($namachief)){}相同,我这样做了,结果是sameyeah,我在表单上犯了一个错误是的,我在表单上犯了一个错误