如何在模式7中找到MySQL WEEK函数的PHP等价物？

使用PHP，如何查找周数，其中：

一周的第一天是星期一， 第一周是今年第一周有周一， 范围是1-53？ 我正在尝试实现与MySQL代码相当的PHP：

SELECT WEEK(date('Y-m-d'), 7);

如本网站所示：

我试图用错误的语言MySQL实现的示例：

$dbh = new PDO("mysql:host=localhost;dbname=test", "root", "");

$stmt = $dbh->prepare("SELECT WEEK('2012-12-30', 7) as week");
$stmt->execute();
$result = $stmt->fetch(PDO::FETCH_ASSOC);
echo "2012-12-30 = ".$result['week']."<br />";

$stmt = $dbh->prepare("SELECT WEEK('2012-12-31', 7) as week");
$stmt->execute();
$result = $stmt->fetch(PDO::FETCH_ASSOC);
echo "2012-12-31 = ".$result['week']."<br />";

$stmt = $dbh->prepare("SELECT WEEK('2013-01-01', 7) as week");
$stmt->execute();
$result = $stmt->fetch(PDO::FETCH_ASSOC);
echo "2013-01-01 = ".$result['week']."<br />";

$stmt = $dbh->prepare("SELECT WEEK('2013-01-06', 7) as week");
$stmt->execute();
$result = $stmt->fetch(PDO::FETCH_ASSOC);
echo "2013-01-06 = ".$result['week']."<br />";

$stmt = $dbh->prepare("SELECT WEEK('2013-01-07', 7) as week");
$stmt->execute();
$result = $stmt->fetch(PDO::FETCH_ASSOC);
echo "2013-01-07 = ".$result['week']."<br />";

我的尝试：使用正确的语言PHP，但结果错误

$date = new DateTime('2012-12-30');
echo "2012-12-30 = ".$date->format('W')."<br />";
$date = new DateTime('2012-12-31');
echo "2012-12-31 = ".$date->format('W')."<br />";
$date = new DateTime('2013-01-01');
echo "2013-01-01 = ".$date->format('W')."<br />";
$date = new DateTime('2013-01-06');
echo "2013-01-06 = ".$date->format('W')."<br />";
$date = new DateTime('2013-01-07');
echo "2013-01-07 = ".$date->format('W')."<br />";

我觉得我错过了一些基本的东西。在此方面的任何帮助都将非常感谢，并提前向您表示感谢

应该会帮助你。在您的情况下，这段代码应该满足您的要求：

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strftime%V，strotime'2013-01-21'

基于ISO标准PHP是正确的。有关%V的更多信息是ISO对“周”的定义，这不是询问者想要的。有%U和%W可能生成预期的一周。我已尝试回显strftime%V，strotime'2013-01-01'；但由于某种原因，我什么也得不到。然后我尝试了echo strftime%W，strotime'2013-01-01'和echo strftime%U，strotime'2013-01-01'，但都给出了0，但我试图得到1。从那以后，我设法改变了需求，他们接受了ISO标准，这意味着不再需要，但问题仍然很有趣。

$date = new DateTime('2012-12-30');
echo "2012-12-30 = ".$date->format('W')."<br />";
$date = new DateTime('2012-12-31');
echo "2012-12-31 = ".$date->format('W')."<br />";
$date = new DateTime('2013-01-01');
echo "2013-01-01 = ".$date->format('W')."<br />";
$date = new DateTime('2013-01-06');
echo "2013-01-06 = ".$date->format('W')."<br />";
$date = new DateTime('2013-01-07');
echo "2013-01-07 = ".$date->format('W')."<br />";

2012-12-30 = 52
2012-12-31 = 01
2013-01-01 = 01
2013-01-06 = 01
2013-01-07 = 02