Php 如何在preg\u match\u all中将多个值组合在一起

嘿，朋友们，我对PHP中的

preg\u match\u all

有问题

我有这样的输出

"offerId" : 104, 
"offerName" : "Abcd", 
"alertText" : null,
"payoutType" : "REGISTER", 
"payoutDetails" : [ 
    { "propertyName" : "REGISTER",
      "propertyValue" : "1.0",
      "offerId" : 105, 
      "alertText" : null,
      "payoutType" : "REGISTER",
      "offerName" : "Abcdeeee", 
      "payoutDetails" : [ 
          { "propertyName" : "REGISTER",
            "propertyValue" : "1.0",
            "offerId" : 106,
            "offerName" : "Abcde", 
            "alertText" : null,
            "payoutType" : "REGISTER",
            "payoutDetails" : [
                { "propertyName" : "REGISTER",
                  "propertyValue" : "1.0"

现在，我想根据报价id 1 x 1以这种格式保存值

offerid:-104 :offername-abcd:propertyValue:-1.0

我尝试了

preg\u match\u all

，但它不能同时处理所有值

---

以给定格式存储值的最佳方法是什么？输出不完整。看起来像JSON？ 无论如何，如果删除了多余的空间：

$regex= "/\"offerId\" : (.*?), \"offerName\" : \"(.*?)\"/ms";

$subject='
"offerId" : 104, 
"offerName" : "Abcd", 
"alertText" : null,
"payoutType" : "REGISTER", 
"payoutDetails" : [ 
    { "propertyName" : "REGISTER",
      "propertyValue" : "1.0",
      "offerId" : 105, 
      "offerName" : "Abcdeeee",
      "alertText" : null,
      "payoutType" : "REGISTER", 
      "payoutDetails" : [ 
          { "propertyName" : "REGISTER",
            "propertyValue" : "1.0",
            "offerId" : 106,
            "offerName" : "Abcde", 
            "alertText" : null,
            "payoutType" : "REGISTER",
            "payoutDetails" : [
                { "propertyName" : "REGISTER",
                  "propertyValue" : "1.0"
                  ';
$subject = preg_replace('/\s+/', ' ', $subject);

preg_match_all($regex, $subject, $matches);

print_r( $matches);

---

运行代码：https://3v4l.org/WHaon

您的输出不完整。。。请发布完整的输出（或至少是一个可用的子集），并按照我在编辑中所做的那样对其进行格式化。对于[0-9]之类的数字，此解决方案最好使用正则表达式+