Php 如果(html==true)不满足此条件
从表中检查电子邮件和密码后,它将进入studentDashBoard.php文件。但每次我得到错误,它给错误的id或psd 以下是我的html标记:Php 如果(html==true)不满足此条件,php,jquery,html,mysql,Php,Jquery,Html,Mysql,从表中检查电子邮件和密码后,它将进入studentDashBoard.php文件。但每次我得到错误,它给错误的id或psd 以下是我的html标记: login.php: <form action="login.php" id="LoginForm" name="LoginForm" method="post" onsubmit=" return validate();"> <div class="form-group">
login.php
:
<form action="login.php" id="LoginForm" name="LoginForm" method="post" onsubmit=" return validate();">
<div class="form-group">
<label for="exampleInputEmail1">Email address</label>
<div class="input-group">
<span class="input-group-addon" id="basic-addon1"><span class="glyphicon glyphicon-user"></span></span>
<input type="email" name="email" class="form-control" id="exampleInputEmail1" placeholder="Enter email" required>
</div>
<p id="statusEmail"></p>
</div>
<div class="form-group">
<label for="exampleInputPassword1">Password</label>
<div class="input-group">
<span class="input-group-addon" id="basic-addon1"><span class="glyphicon glyphicon-star"></span></span>
<input type="password" name="password"class="form-control" id="exampleInputPassword1" placeholder="Password" required>
</div>
<p id="statusPsd"></p>
</div>
<hr/>
<p id="status"></p>
<button type="button" class="btn btn-success"><span class="glyphicon glyphicon-arrow-left">Back</button>
<button type="submit" name="submit" id="loginButton" class="btn btn-primary"><span class="glyphicon glyphicon-lock">Login</button>
<p><br/></p>
<p id="notice"> If not registered yet</p><br/>
<button type="button" id="SignUp" class="btn btn-danger">SingUp</button>
</form>
studentDashBoard.php
文件只是打印“hi”而已,没有其他内容
如果您需要更多详细信息,请让我知道尝试使用您的
If
条件,如下所示:
if(html==“true”)
{}替换
success:function(html)
{
if(html==true)
{
}
}
有点像
success:function(html)
{
if($('#result').html(html)==true)
{
{
}
而不是:
if(isset($\u POST['submit'])){
}
在studentLogin.php
文件中,我改为
if(isset($\u POST['email'])和&isset($\u POST['password']))
{
现在它工作了试试这个
success:function(html){console.log(html);}
,检查php文件实际返回的内容。它将显示在控制台中。试试echo json_encode('false');
success:function(html)
{
if(html==true)
{
}
}
success:function(html)
{
if($('#result').html(html)==true)
{
{
}