PHP在多个数组中计算相似值

我在数据库中有如下值：

Row 1 : ["2","3"]
Row 2 : ["1","3"]
Row 3 : ["2","3","4"]

Array ( [0] => 2 [1] => 3 ) 
Array ( [0] => 1 [1] => 3 )
Array ( [0] => 2 [1] => 3 [2] => 4 )

在前端，我选择了所有行，现在我想显示类似值的计数。 例如：上述代码中的所需o/p：1=1、2=2、3=3、4=1的计数

当我对上述值进行json_解码并使用print_r时，我得到如下结果：

Row 1 : ["2","3"]
Row 2 : ["1","3"]
Row 3 : ["2","3","4"]

Array ( [0] => 2 [1] => 3 ) 
Array ( [0] => 1 [1] => 3 )
Array ( [0] => 2 [1] => 3 [2] => 4 )

注意：行列表可以增加，如何找到类似的值

我尝试了如图所示的数组_intersect，但没有成功

例如：这里的图像

获取上述数据的代码：

    $conn = new mysqli("localhost", "root", "", "ams");
    $query="SELECT * FROM attendance WHERE subject = '$subj'";
    $result = $conn->query($query);


<table class="table table-responsive">
            <tr>
                <th>Sr. No</th>
                <th>Col 1 </th>
                <th>Col 2</th>
            </tr>
            <form method="post">
                <?php
                $i=1;
                    if (mysqli_num_rows($result) > 0) {
                        while ($row=mysqli_fetch_assoc($result)) {

                            $data = $row['att'];
                            $data = json_decode($data);

                            echo "<tr>";
                            echo "<td>" . $i . "</td>";
                            echo "<td>" . $row['date1'] . "</td>";
                            echo "<td>" . print_r($data) . "</td>";
                            echo "</tr>";
                            $i++;
                        }
                    }
                ?>
            </form>
            </table>

$conn=newmysqli（“localhost”、“root”、“ams”）；
$query=“从主题为“$subj”的考勤中选择*；
$result=$conn->query（$query）；
高级工程师
第1列
第2列

所以，我为你上了这门课。它将在初始化时创建连接

class RowData {

    private $connection;
    private $returnContent = array();
    private $stmt = null;

    function __construct() {
        $connection = new PDO("mysql:host=" . MYSQL_HOST . ";dbname=" . MYSQL_DB, MYSQL_USERNAME, MYSQL_PASSWORD);
        $connection->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
        $connection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
        $this->connection = $connection;
    }

    public function get($subj) {
        $this->getContentFromDB($subj);
        $this->parseContent();
        return $this->returnContent;
    }

    private function getContentFromDB($subj) {
        $stmt = $this->connection->prepare("SELECT * FROM attendance WHERE subject = '{$subj}'");
        $stmt->execute();
        $this->stmt = $stmt;
    }

    private function parseContent() {
        $content = $stmt->fetchAll(PDO::FETCH_OBJ);
        if(count($content) < 1) {
            throw new Exception('Unable to find any attendies');
        }
        foreach($content as $values) {
            $row = $this->getJsonArray($values->att);
            $this->findValues($row);
        }
    }

    private function getJsonArray($content) {
        return json_decode($content);
    }

    private function findValues(array $row) {
        foreach($row as $key => $value) {
            if(isset($this->returnContent[$value])) {
                $this->returnContent[$value] = $this->returnContent[$value] + 1;
            } else {
                $this->returnContent[$value] = 1;
            }
        }
        return;
    }
}

要使用该类，您可以编写如下内容：

$rowData = new RowData();
try {
    $content = $rowData->get();
} catch (Exception $e) {
    // No results were found
}

---

希望这有帮助！如果你需要帮助实现这一点，让我知道，我会非常乐意帮助你

所以，我给你上了这门课。它将在初始化时创建连接

class RowData {

    private $connection;
    private $returnContent = array();
    private $stmt = null;

    function __construct() {
        $connection = new PDO("mysql:host=" . MYSQL_HOST . ";dbname=" . MYSQL_DB, MYSQL_USERNAME, MYSQL_PASSWORD);
        $connection->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
        $connection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
        $this->connection = $connection;
    }

    public function get($subj) {
        $this->getContentFromDB($subj);
        $this->parseContent();
        return $this->returnContent;
    }

    private function getContentFromDB($subj) {
        $stmt = $this->connection->prepare("SELECT * FROM attendance WHERE subject = '{$subj}'");
        $stmt->execute();
        $this->stmt = $stmt;
    }

    private function parseContent() {
        $content = $stmt->fetchAll(PDO::FETCH_OBJ);
        if(count($content) < 1) {
            throw new Exception('Unable to find any attendies');
        }
        foreach($content as $values) {
            $row = $this->getJsonArray($values->att);
            $this->findValues($row);
        }
    }

    private function getJsonArray($content) {
        return json_decode($content);
    }

    private function findValues(array $row) {
        foreach($row as $key => $value) {
            if(isset($this->returnContent[$value])) {
                $this->returnContent[$value] = $this->returnContent[$value] + 1;
            } else {
                $this->returnContent[$value] = 1;
            }
        }
        return;
    }
}

要使用该类，您可以编写如下内容：

$rowData = new RowData();
try {
    $content = $rowData->get();
} catch (Exception $e) {
    // No results were found
}

---

希望这有帮助！如果你需要帮助实现这一点，让我知道，我会非常乐意帮助你

我很困惑。你用的是什么数据库？我用的是MYSQL数据库你不应该得到这样的回应。您使用什么驱动程序连接到Mysql？你能在这个问题上给出一些代码吗。这很模糊。我可以用PDO给你一个答案吗？我不太清楚如何利用

mysqli\ucode>？@McStuffins：是的，没有问题，我很困惑。你用的是什么数据库？我用的是MYSQL数据库你不应该得到这样的回应。您使用什么驱动程序连接到Mysql？你能在这个问题上给出一些代码吗。这很模糊。我可以用PDO给你一个答案吗？我不太清楚如何利用
mysqli\ucode>？@McStuffins:是的，没有问题