Php can'；当值中出现空格时，无法工作url重写

当我传递包含空格的值时，我的URL重写不起作用（比如新德里） 看到我的代码了吗

RewriteRule top-indian-cities-states-(\d+)/(.*)/ top-indian-cities-states.php?id=$1&top=$2

当第二个参数变成新德里时，它就不起作用了

mydomain/top-indian-cities-states-1/New-delhi-Hotel

我已将变量指定为

$name="New Delhi";
$displayName=trim($name." Hotel");
        $urlVal=str_replace(" ","-",$displayName);
<li><a href="top-indian-cities-states-1/<?=$urlVal?> /"><?=$name?> Hotel</a></li>

有人有主意吗

请重播

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提前感谢

您在城市名称后指定了一个尾随斜杠，但您的示例中没有该斜杠（不允许使用空格）

2种解决方案：

将尾部斜杠添加到正则表达式：

RewriteRule top-indian-cities-states-(\d+)/(.*)/? top-indian-cities-states.php?id=$1&top=$2

将尾部斜杠添加到变量中

$urlVal=str_replace(" ","-",$displayName);
$urlVal=. "/";

并在HTML中删除斜杠

试试这个：

$urlVal=trim(str_replace(" ","-",$displayName));

<li><a href="top-indian-cities-states-1/<?=$urlVal?>/"><?=$name?> Hotel</a></li>

$urlVal=trim（str_replace（“，”-“，$displayName））；

尝试这样的重写规则

RewriteRule top-indian-cities-states-(\d+)/(.*)$ top-indian-cities-states.php?id=$1&top=$2


<li><a href="top-indian-cities-states-1/<?=$urlVal?> /"

RewriteRule top indian cities State-（\d+/（*）$top indian cities State.php？id=$1&top=$2

RewriteRule top-indian-cities-states-(\d+)/(.*)$ top-indian-cities-states.php?id=$1&top=$2


<li><a href="top-indian-cities-states-1/<?=$urlVal?> /"

<li><a href="top-indian-cities-states-1/<?=$urlVal?>"