Php 计算同一mysql请求中的多个特定值

是否可以这样做：

SELECT *, 
COUNT(* WHERE media_id = 1) as count_1, 
COUNT(* WHERE media_id = 2) as count_2 
WHERE user_id = 1

还是我必须单独提问

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谢谢。

您可以使用条件和作为

select
sum(media_id = 1) as count_1,
sum(media_id = 2) as count_2 
from table_name
where user_id = 1;

请注意，使用聚合函数对select*

没有意义是的，这是可能的

请尝试以下示例：

select 
(select count(*) from TableA where 1=1) as totalA,
(select count(*) from TableB where 1=1) as totalB,
(select count(*) from TableC where 1=1) as totalc