Php 分隔表中行的值

我计划将一个查询放入我的变量中，但我的问题是我需要将一组不同的值分组，以便在我的PHP输出中将它们分开。我想知道这是否可行，即使对SQL查询有帮助也会有很大帮助。请参见我的屏幕截图：

如果您查看表格

部分

列的底部，您将看到一个

GI21

和

GI122

。我现在使用的查询是这样的

SELECT `scstock`.*, `schead`.* FROM `scstock` LEFT JOIN `schead` ON schead.TrNo = scstock.TrNo WHERE (`schead`.`curriculumcode`='BSIT 2011') AND (`schead`.`styear`='4') AND (`schead`.`terms`='1ST') AND (`schead`.`isBlock`=1)

还是用Yii

->select(['scstock.*', 'schead.*'])
    ->leftJoin('schead', 'schead.TrNo = scstock.TrNo')
    ->where(['schead.curriculumcode' => $curriculumcode,
              'schead.styear' => $year,
              'schead.terms' => $term,
              'schead.isBlock' => 1
              ])
    ->asArray()
    ->all();

这将输出所有行，这些行具有

isBlock=1

，但我需要做的是分离

GI21

和

GI122

，可能现在就将它们放在一个数组中，但可能有更好的实现，但现在在将它们放在一个数组中之后，我返回它们，将它们放在这样一个表的视图中

 <table class="table table-bordered" id="studentTable">
              <th>Subject</th>
              <th>Schedule</th>
              <th>Section</th>
              <th>Action</th>
              <th>Slots</th>
              <th>Status</th>
          <?php foreach($getBlock as $values): ?>

                  <tr>
                    <td><?= $values['subjectcode']; ?></td>
                    <td><?= $values['schedday'] . ' ' . $values['schedtime'] ?></td>
                    <td><?= $values['section'] ?></td>
                    <td><?= '....' ?></td>
                    <td><?= $values['slots'] ?></td>
                    <td><?= '....' ?></td>
                  </tr>

          <?php endforeach; ?>
              </table>

主题
日程
部分
行动
槽
地位

---

现在要在视图中分离它们，也许我只需将

foreach

放在

表中

标记来分离部分？如何将不同的一组值分组以在PHP输出中分离它们？任何类型的帮助都将不胜感激。

您可以使用两个单独的查询，一个用于not（G121和GI122）例如：getBlock1

->select(['scstock.*', 'schead.*'])
    ->leftJoin('schead', 'schead.TrNo = scstock.TrNo')
    ->where(['schead.curriculumcode' => $curriculumcode,
              'schead.styear' => $year,
              'schead.terms' => $term,
              'schead.isBlock' => 1,
              'not in','schead.section',['G121', 'GI122'],
              ])
    ->asArray()
    ->all();

第二个是in（G121和GI122），例如：getBlock2

where(['not in','attribute',$array]);



->select(['scstock.*', 'schead.*'])
    ->leftJoin('schead', 'schead.TrNo = scstock.TrNo')
    ->where(['schead.curriculumcode' => $curriculumcode,
              'schead.styear' => $year,
              'schead.terms' => $term,
              'schead.isBlock' => 1,
              'in','schead.section',['G121', 'GI122'],
              ])
    ->asArray()
    ->all();

---

您可以在第一个foreach中关联到$getBlock1，在第二个foreach中关联到$getBlock2，您可以使用两个单独的查询，一个用于not（G121和GI122），例如：getBlock1

->select(['scstock.*', 'schead.*'])
    ->leftJoin('schead', 'schead.TrNo = scstock.TrNo')
    ->where(['schead.curriculumcode' => $curriculumcode,
              'schead.styear' => $year,
              'schead.terms' => $term,
              'schead.isBlock' => 1,
              'not in','schead.section',['G121', 'GI122'],
              ])
    ->asArray()
    ->all();

where(['not in','attribute',$array]);



->select(['scstock.*', 'schead.*'])
    ->leftJoin('schead', 'schead.TrNo = scstock.TrNo')
    ->where(['schead.curriculumcode' => $curriculumcode,
              'schead.styear' => $year,
              'schead.terms' => $term,
              'schead.isBlock' => 1,
              'in','schead.section',['G121', 'GI122'],
              ])
    ->asArray()
    ->all();

第二个是in（G121和GI122），例如：getBlock2

where(['not in','attribute',$array]);



->select(['scstock.*', 'schead.*'])
    ->leftJoin('schead', 'schead.TrNo = scstock.TrNo')
    ->where(['schead.curriculumcode' => $curriculumcode,
              'schead.styear' => $year,
              'schead.terms' => $term,
              'schead.isBlock' => 1,
              'in','schead.section',['G121', 'GI122'],
              ])
    ->asArray()
    ->all();

您可以在第一个foreach中关联$getBlock1，在第二个foreach中关联$getBlock2

where(['not in','attribute',$array]);



->select(['scstock.*', 'schead.*'])
    ->leftJoin('schead', 'schead.TrNo = scstock.TrNo')
    ->where(['schead.curriculumcode' => $curriculumcode,
              'schead.styear' => $year,
              'schead.terms' => $term,
              'schead.isBlock' => 1,
              'in','schead.section',['G121', 'GI122'],
              ])
    ->asArray()
    ->all();