SSH2如果登录失败=退出。PHP
如果登录到ssh2失败,我将如何生成此代码、退出或退出SSH2如果登录失败=退出。PHP,php,Php,如果登录到ssh2失败,我将如何生成此代码、退出或退出 $query = mysql_query("SELECT * FROM ssh2"); while($row = mysql_fetch_array($query)){ $ip = $row['ip']; $user = $row['user']; $pass = $row['pass']; $ss
$query = mysql_query("SELECT * FROM ssh2");
while($row = mysql_fetch_array($query)){
$ip = $row['ip'];
$user = $row['user'];
$pass = $row['pass'];
$ssh = ssh2_connect($ip, 22);
ssh2_auth_password($ssh, $user, $pass);
有关的文件说:
成功时返回TRUE,失败时返回FALSE
因此,您可以检查它是否返回false
if(ssh2_auth_password($ssh, $user, $pass) === false) {
//do stuff if it can't login
}
在执行此操作时,您可能还希望在ssh2\u connect()
调用中添加一些错误检查,因为如果无法连接,它可能会返回非资源
$ssh = ssh2_connect($ip, 22);
if($ssh === false) {
//do stuff if it can't connect
}
编辑以供评论
如果你想让它在另一次登录尝试中回退,你可以用几种方法。如果您只需要再拥有一组凭据,则只需在其内部复制If
//try the first login
if(ssh2_auth_password($ssh, $user, $pass) === false) {
//try the second set
if(ssh2_auth_password($ssh, $user2, $pass2) === false) {
//do stuff if it can't login
}
}
或者,如果您有大量凭据要尝试,您可以将它们存储在一个数组中并在其上循环
$creds = array(
array('user' => $user, 'pass' => $pass),
array('user' => $user2, 'pass' => $pass2),
//etc
);
$logged_in = false;
foreach($creds as $cred) {
if(ssh2_auth_password($ssh, $cred['user'], $cred['pass'])) {
$logged_in = true;
break;
}
}
if(!$logged_in) {
//do stuff when you can't login
}
我更喜欢使用异常来处理以下内容:
try {
if (!$query = mysql_query("SELECT * FROM ssh2")) {
throw new Exception("MySQL query failed.");
}
while($row = mysql_fetch_array($query)){
$ip = $row['ip'];
$user = $row['user'];
$pass = $row['pass'];
$ssh = ssh2_connect($ip, 22);
if ($ssh === false) {
throw new Exception("Connection to $ip:22 failed");
}
if (ssh2_auth_password($ssh, $user, $pass) === false) {
throw new Exception("Password failed for user '".$user."'");
}
}
}
catch (Exception $e) {
echo 'Caught exception: ', $e->getMessage(), "\n";
}
好的,这段代码以任何方式工作,我可以使它,所以当它失败时,它将跳过它,并使用不同的ssh2 loginEdited我的答案。如果答案确实回答了您的问题,请不要忘记标记“接受答案”。