Php 通过PDO获取所有记录

尝试从表中提取所有数据，但既不显示数据也不显示任何错误。我知道我错过了一些东西，但我不知道到底是什么

<?php
$st = $pdo->prepare("SELECT plan_id, plan_name, zone_id, operator_price, selling_price, validity, plan_type FROM plan_tbl");
$st->execute();
$cnt=$st->rowCount();
$user_record=$st->fetchAll();
}
catch (PDOException $ex) {
    echo  $ex->getMessage();
}
$rowdata="<tbody>";
foreach($plan_record as $plan_record1){
    $rowdata.="<tr>";
    $sr_no = $plan_record1['plan_id'];
    $plan_name = $plan_record1['plan_name'];
    //$user_fullname = $user_record1['fname'] . " " . $user_record1['mname'] . " " . $user_record1['lname'];
    //echo $user_fullname;
    $zone_id = $plan_record1['zone_id'];
    $operator_price = $plan_record1['operator_price'];
    $selling_price = $plan_record1['selling_price'];
    $validity = $plan_record1['validity'];
    $plan_type = $plan_record1['plan_type'];
    $icon="<i class='fa fa-pencil-square-o pad' aria-hidden='true'></i><i class='fa fa-times pad' aria-hidden='true'></i>";
    $rowdata.="</tr>";
}
?>

使用$user\u记录而不是$plan\u记录，因为您没有在代码中声明它

foreach($user_record as $plan_record1){
    $rowdata.="<tr>";
    $sr_no = $plan_record1['plan_id'];
    $plan_name = $plan_record1['plan_name'];
    //$user_fullname = $user_record1['fname'] . " " . $user_record1['mname'] . " " . $user_record1['lname'];
    //echo $user_fullname;
    $zone_id = $plan_record1['zone_id'];
    $operator_price = $plan_record1['operator_price'];
    $selling_price = $plan_record1['selling_price'];
    $validity = $plan_record1['validity'];
    $plan_type = $plan_record1['plan_type'];
    $icon="<i class='fa fa-pencil-square-o pad' aria-hidden='true'></i><i class='fa fa-times pad' aria-hidden='true'></i>";
    $rowdata.="</tr>";
}

---

我会使用有意义的变量名，比如$plans和$plan。还要注意的是，你不是

<?php
$st = $pdo->prepare("SELECT plan_id, plan_name, zone_id, operator_price, selling_price, validity, plan_type FROM plan_tbl");
$st->execute();
$cnt=$st->rowCount();
$plans=$st->fetchAll();
}
catch (PDOException $ex) {
    echo  $ex->getMessage();
}
$rowdata="<tbody>";
foreach($plans as $plan){
    $rowdata.="<tr>";
    $rowdata .= "<td>{$plan['plan_id']}</td>";
    $rowdata .= "<td>{$plan['plan_name']}</td>";
    $rowdata .= "<td>{$plan['zone_id']}</td>";
    $rowdata .= "<td>{$plan['operator_price']}</td>";
    $rowdata .= "<td>{$plan['selling_price']}</td>";
    $rowdata .= "<td>{$plan['validity']}</td>";
    $rowdata .= "<td>{$plan['plan_type']}</td>";
    $rowdata .= "<td><i class='fa fa-pencil-square-o pad' aria-hidden='true'></i><i class='fa fa-times pad' aria-hidden='true'></i></td>";
    $rowdata.="</tr>";
}
$rowdata .= "</tbody>";

echo $rowdata;

退出循环后，请确保使用以下内容显示循环：

echo $rowdata

---

我还带出了youclosing？>标记，因为如果它位于文件的末尾，可能会导致一些问题

塔克斯！它现在工作得很好。。！塔克斯！现在我的记录已被提取，但未显示在表中！你把我的prblm弄对了？？是的，$sr_no中存储的数据每次回到foreach循环时都会被擦除。因此，您只会得到$sr_no变量中检索到的最后一个值。相反，只需像我上面展示的那样将数据附加到$rowdata即可。明白了！！现在工作完美！！非常感谢。我错过了下面的部分！这是完美的代码！！谢谢你的帮助！我也会尝试接球，因为它是，因为它是

$sr_no = $plan['plan_id'];

echo $rowdata