Php 从表中选择以插入如下新值。正如Thorsten所说,使用值插入将起作用。 ALTER TABLE `companies` ADD PRIMARY KEY( `name_employee`, `email`); name_empl
从表中选择以插入如下新值。正如Thorsten所说,使用值插入将起作用。Php 从表中选择以插入如下新值。正如Thorsten所说,使用值插入将起作用。 ALTER TABLE `companies` ADD PRIMARY KEY( `name_employee`, `email`); name_empl,php,mysql,primary-key,composite-primary-key,Php,Mysql,Primary Key,Composite Primary Key,从表中选择以插入如下新值。正如Thorsten所说,使用值插入将起作用。 ALTER TABLE `companies` ADD PRIMARY KEY( `name_employee`, `email`); name_employee = 'Pavlos Pavlos' email = 'company_Name@gmail.com' name_employee = 'John John' email = 'company_Name@gmail.com' nam
ALTER TABLE `companies`
ADD PRIMARY KEY(
`name_employee`,
`email`);
name_employee = 'Pavlos Pavlos'
email = 'company_Name@gmail.com'
name_employee = 'John John'
email = 'company_Name@gmail.com'
name_employee = 'Nick Nick'
email = 'company_Name@gmail.com'
SELECT
name, account_number, dateExp, credit_limit, amount_debt, balance,
'Nick Nick', '250', 'company_Name@gmail.com', 'pass'
FROM companies
WHERE email='company_Name@gmail.com'