Php 要使用MySQL组将两行合并为一行吗

我想使用

group\u concat

mysql查询将两行合并为一行

$query = $this->db->select('trt.day, group_concat(trt.open_time, trt.close_time)')
                          ->from('tbl_restaurant_timing as trt')
                          ->where('trt.restaurant_id', $restaurant_id, FALSE)
                          ->group_by('trt.day')
                          ->get();

我已经尝试了上面的一个，但它提供了一些其他的结果如下

Array
(
    [0] => Array
        (
            [day] => Fri
            [group_concat(trt.open_time, trt.close_time)] => 18:0023:00,10:0015:00
        )

    [1] => Array
        (
            [day] => Mon
            [group_concat(trt.open_time, trt.close_time)] => 10:0015:00,18:0023:00
        )

    [2] => Array
        (
            [day] => Sat
            [group_concat(trt.open_time, trt.close_time)] => 18:0023:00,10:0015:00
        )

    [3] => Array
        (
            [day] => Sun
            [group_concat(trt.open_time, trt.close_time)] => 10:0015:00,18:0023:00
        )

    [4] => Array
        (
            [day] => Thu
            [group_concat(trt.open_time, trt.close_time)] => 10:0015:00,18:0023:00
        )

    [5] => Array
        (
            [day] => Tue
            [group_concat(trt.open_time, trt.close_time)] => 18:0023:00,10:0015:00
        )

    [6] => Array
        (
            [day] => Wed
            [group_concat(trt.open_time, trt.close_time)] => 18:0023:00,10:0015:00
        )

)

在这里，您可以看到第二个插槽位于某些行的第一位，这是错误的

这是我的一个表，我希望php表中的结果如下所示

Array
(
    [0] => Array
        (
            [day] => Fri
            [group_concat(trt.open_time, trt.close_time)] => 18:0023:00,10:0015:00
        )

    [1] => Array
        (
            [day] => Mon
            [group_concat(trt.open_time, trt.close_time)] => 10:0015:00,18:0023:00
        )

    [2] => Array
        (
            [day] => Sat
            [group_concat(trt.open_time, trt.close_time)] => 18:0023:00,10:0015:00
        )

    [3] => Array
        (
            [day] => Sun
            [group_concat(trt.open_time, trt.close_time)] => 10:0015:00,18:0023:00
        )

    [4] => Array
        (
            [day] => Thu
            [group_concat(trt.open_time, trt.close_time)] => 10:0015:00,18:0023:00
        )

    [5] => Array
        (
            [day] => Tue
            [group_concat(trt.open_time, trt.close_time)] => 18:0023:00,10:0015:00
        )

    [6] => Array
        (
            [day] => Wed
            [group_concat(trt.open_time, trt.close_time)] => 18:0023:00,10:0015:00
        )

)

---

所以请检查我哪里错了。谢谢

请找到下面提到的解决方案，操作有点冗长，但我认为这将对您有所帮助

SELECT 
    trt.id,
    trt.day, 
    (SELECT CONCAT_WS('-',open_time, close_time) from tbl_restaurant_timing trt1 WHERE trt1.day = trt.day ORDER BY trt1.id ASC LIMIT 1) as first_slot,
    (SELECT CONCAT_WS('-',open_time, close_time) from tbl_restaurant_timing trt1 WHERE trt1.day = trt.day ORDER BY trt1.id DESC LIMIT 1) as second_slot
FROM tbl_restaurant_timing trt
WHERE trt.restaurant_id = 1
GROUP BY trt.day
ORDER BY id;

表格数据

结果

---

如果不起作用，请告诉我。

至少，您应该尝试自己编写代码。之后，如果你有问题，你可以张贴你已经尝试了一个明确的解释什么是不工作，并提供一个解决方案。我建议你读一个好的问题和答案。另外，一定要把答案拿出来阅读。请向上投票，这样其他开发者也能从你的答案中受益。谢谢你的解决方案

+----+-----------+-------------+-------------+
| id | day       | first_slot  | second_slot |
+----+-----------+-------------+-------------+
| 1  | Monday    | 10:00-15:00 | 18:00-23:50 |
+----+-----------+-------------+-------------+
| 3  | Tuesday   | 09:00-15:00 | 18:00-23:00 | 
+----+-----------+-------------+-------------+
| 6  | Wednesday | 10:00-15:00 | 18:00-23:00 |  
+----+-----------+-------------+-------------+
| 8  | Thursday  | 10:00-15:00 | 18:00-23:00 | 
+----+-----------+-------------+-------------+
| 13 | Friday    | 10:00-15:00 | 18:00-23:00 | 
+----+-----------+-------------+-------------+
| 15 | Saturday  | 10:00-15:00 | 18:00-23:00 |
+----+-----------+-------------+-------------+
| 17 | Sunday    | 10:00-15:00 | 18:00-23:00 |
+----+-----------+-------------+-------------+