Php 统计并检查json查询结果
我正在处理三种情况: 1) 如果查询没有返回结果 2) 如果查询返回一个结果 3) 如果查询返回两个或多个结果 这是我的疑问:Php 统计并检查json查询结果,php,mysql,json,laravel,Php,Mysql,Json,Laravel,我正在处理三种情况: 1) 如果查询没有返回结果 2) 如果查询返回一个结果 3) 如果查询返回两个或多个结果 这是我的疑问: $events = DB::table('bookings') ->join('events','bookings.event_id','=','events.id') ->join('spots','bookings.spot_id','=','spots.id') ->j
$events = DB::table('bookings')
->join('events','bookings.event_id','=','events.id')
->join('spots','bookings.spot_id','=','spots.id')
->join(DB::raw('(select S.event_id,sum(S.spaces) as sum_spaces from spots S group by S.event_id) d'), function($join)
{
$join->on('bookings.event_id', '=', 'd.event_id');
})
->select('bookings.event_id','events.name', 'spots.event_date','d.sum_spaces',
DB::raw('COUNT(bookings.event_id) as tb'))
->groupBy('bookings.event_id')
->get();
我得到json格式的$events,如下所示:
[] = 0
[{"event_id":1,"name":"Yoga","event_date":"2016-05-02","sum_spaces":"450","tb":6}] = 1
[{"event_id":1,"name":"Yoga","event_date":"2016-05-02","sum_spaces":"100","tb":16},{"event_id":2,"name":"Yoga","event_date":"2016-05-02","sum_spaces":"450","tb":6},{"event_id":3,"name":"blah","event_date":"2016-05-02","sum_spaces":"250","tb":6}] = 3
如果你看到0,1和3。对于给定的结果查询,这就是我想要知道的。
我需要检查上面的结果是否有多少个结果。我怎么能找到这个
因为这就是我处理场景的方式:
if(empty($events))
{
//sets default value
}
else if(check if $results have one and only one result)
{
//Do something
}
else
{
//here I can handle if $events query have more than one result.
}
如果我理解正确,您需要:
哦,哇,就是这么简单。我回来了,它看起来像一个json。所以我想知道如何对json进行计数。但我现在明白了。仅当返回到视图时才显示其json。谢谢你的解决方案
$numberOfResults = count($events);