使用PHP、Javascript和JSON创建下拉过滤器

我想做的是创建一个下拉菜单，当您选择一个项目时，页面立即刷新，只显示用户选择的过滤元素

以下是基本HTML：

<SELECT>
 <OPTION selected>Show All</OPTION>
 <OPTION>Color</OPTION>
 <OPTION>Shape</OPTION></SELECT>

PHP将收集用于过滤器的信息：

for ($i = 0; $i < count($json["table"]); $i++) {
 $name = $json["table"][$i]["name"];
 $type = $json["table"][$i]["type"];
 if ($type == "color") {
  // Refresh to show only words of color upon selecting Color from the menu
 }
 else if ($type == "shape") {
  // Refresh to show only words of shape upon selecting Shape from the menu
 }
 else {
  // Refresh to show everything by default or when selecting Show All from the menu
 }
}

---

如何创建此下拉菜单，使其执行指定的操作？我肯定会涉及到Javascript，因为此人发布了一个演示，正好演示了我想要的内容——但我不知道如何实现这一点。

好吧，首先让我说，我认为您最好在Javascript中解析JSON

$(function () {
    var tblData = {
        "table": [{
            "name": "orange",
                "type": "color"
        }, {
            "name": "hexagon",
                "type": "shape"
        }, {
            "name": "red",
                "type": "color"
        }, {
            "name": "square",
                "type": "shape"
        }, {
            "name": "yellow",
                "type": "color"
        }, {
            "name": "blue",
                "type": "color"
        }, {
            "name": "triangle",
                "type": "shape"
        }, {
            "name": "circle",
                "type": "shape"
        }, {
            "name": "green",
                "type": "color"
        }, {
            "name": "pentagon",
                "type": "shape"
        }, {
            "name": "violet",
                "type": "color"
        }]
    };

    var objData = $.parseJSON(tblData);
    $.each(objData, function (i, v) {
        if (v[i].type == 'color') {
            $('#colors').append(v[i].name);
        } else {
            $('#shapes').append(v[i].name);
        }
    });
    $(document).on('change','#selType', function() {
        $('.twoDIVS').hide();
        var strType = $('option:selected',this).val();
        $('#' + strType).show();
    });
});

HTML

---

这应该包含足够的提示和提示，让你去…：

你是在找人帮你写这些代码，还是只是想知道JavaScript需要什么样子？我已经把SELECTED、table和PHP部分都准备好了。所以，一半一半。让我开始，然后给我一个提示，你认为什么是容易的部分。请注意：我对Javascript几乎没有经验。PHP，我可以接受，即使我对这种语言很少陌生。

$(function () {
    var tblData = {
        "table": [{
            "name": "orange",
                "type": "color"
        }, {
            "name": "hexagon",
                "type": "shape"
        }, {
            "name": "red",
                "type": "color"
        }, {
            "name": "square",
                "type": "shape"
        }, {
            "name": "yellow",
                "type": "color"
        }, {
            "name": "blue",
                "type": "color"
        }, {
            "name": "triangle",
                "type": "shape"
        }, {
            "name": "circle",
                "type": "shape"
        }, {
            "name": "green",
                "type": "color"
        }, {
            "name": "pentagon",
                "type": "shape"
        }, {
            "name": "violet",
                "type": "color"
        }]
    };

    var objData = $.parseJSON(tblData);
    $.each(objData, function (i, v) {
        if (v[i].type == 'color') {
            $('#colors').append(v[i].name);
        } else {
            $('#shapes').append(v[i].name);
        }
    });
    $(document).on('change','#selType', function() {
        $('.twoDIVS').hide();
        var strType = $('option:selected',this).val();
        $('#' + strType).show();
    });
});

<SELECT id="selType">
    <OPTION value="all" selected="selected">Show All</OPTION>
    <OPTION value="color">Color</OPTION>
    <OPTION value="shape">Shape</OPTION>
</SELECT>
<div class="twoDivs" id="colors"></div>
<div class="twoDivs" id="shapes"></div>