如何在php中创建如下所示的多维数组？
大家好，我正在尝试创建一个多维数组，格式如下，但我正在努力做到这一点，任何帮助将不胜感激。多谢各位如何在php中创建如下所示的多维数组？,php,mysql,sql,arrays,sorting,Php,Mysql,Sql,Arrays,Sorting,大家好，我正在尝试创建一个多维数组，格式如下，但我正在努力做到这一点，任何帮助将不胜感激。多谢各位 $movies = array(); $sql = "SELECT u.username AS Username, group_concat(v.title) AS Video_title, group_concat(r.rate) AS Rating FROM `rating` AS r JOIN `uploads` AS v ON r.video_id = v
$movies = array();
$sql = "SELECT u.username AS Username, group_concat(v.title) AS Video_title, group_concat(r.rate) AS Rating
FROM `rating` AS r
JOIN `uploads` AS v ON r.video_id = v.vid_id
JOIN `users` as u ON u.user_id = r.rater_id
GROUP by Username" ;
$query = mysqli_query($conn, $sql);
while($result = mysqli_fetch_assoc($query)){
$movies[] = $result;
}
foreach($movies as $k => $v){
unset($movies[$k]);
$movies[$v['Username']] = $v;
}
foreach($movies as $k => $v){
unset($movies[$k]['Username']);
}
print_r($movies);
[user1] => Array ( [Video_title] => Snakes on the Plane,
Superman Returns,
The Night Listner,
Lady in the Water,
Just my Luck,
You me and Dupree
[Rating] => 3.5,
3.5,
3,
2.5,
3,
2.5
) )
'user1' =>
array('Lady in the Water' => 2.5,
'Snakes on a Plane' => 3.5,
'Just My Luck' => 3.0,
'Superman Returns' => 3.5,
'You, Me and Dupree' => 2.5,
'The Night Listener' => 3.0
)
更改以下行：
$movies[$v['Username']] = $v;
然后再试一次。它将在每次迭代的
Username$movies[$v['Username']] = $v;
然后再试一次。它将在每次迭代的
Username $movies = array();
$sql = "
SELECT u.username AS Username, v.title AS Video_title, r.rate AS Rating
FROM `rating` AS r
JOIN `uploads` AS v ON r.video_id = v.vid_id
JOIN `users` as u ON u.user_id = r.rater_id
GROUP by Username" ;
$query = mysqli_query($conn, $sql);
while($result = mysqli_fetch_assoc($query)){
$movies[$result['Username']][$result['Video_title']] = $result['Rating'];
}
print_r($movies);
为获得瞄准效果，请尝试以下代码：
$movies = array();
$sql = "
SELECT u.username AS Username, v.title AS Video_title, r.rate AS Rating
FROM `rating` AS r
JOIN `uploads` AS v ON r.video_id = v.vid_id
JOIN `users` as u ON u.user_id = r.rater_id
GROUP by Username" ;
$query = mysqli_query($conn, $sql);
while($result = mysqli_fetch_assoc($query)){
$movies[$result['Username']][$result['Video_title']] = $result['Rating'];
}
print_r($movies);
您必须按照以下方式进行操作：-
$movies = array();
$sql = "SELECT u.username AS Username, group_concat(v.title) AS Video_title, group_concat(r.rate) AS Rating
FROM `rating` AS r
JOIN `uploads` AS v ON r.video_id = v.vid_id
JOIN `users` as u ON u.user_id = r.rater_id
GROUP by Username" ;
$query = mysqli_query($conn, $sql);
while($result = mysqli_fetch_assoc($query)){
$movies[] = $result;
}
$new_movies = array(); // a new array variable
foreach($movies as $k => $v){
$array_keys = explode(',',$v['Video_title']); // explode Video_title string into array
$trimmed_array_key=array_map('trim',$array_keys); // trim all spaces from each value of $trimmed_array_key array
$array_values = explode(',',$v['Rating']); // explode Rating array
$trimmed_array_values=array_map('trim',$array_values);//remove all spaces from $trimmed_array_values array
$new_movies[$v['Username']] = array_combine($trimmed_array_key,$trimmed_array_values); // combine $trimmed_array_key array and $trimmed_array_values array and assign to corresponding user
}
echo "<pre/>";print_r($new_movies); // print new array
$movies=数组（）；
$sql=“选择u.username作为用户名，选择group_concat（v.title）作为视频_title，选择group_concat（r.rate）作为评级
从'rating'改为r
在r.video\u id=v.vid\u id上以v的形式加入'uploads'
在u.user\u id=r.rater\u id上以u的身份加入'users'
按用户名分组”；
$query=mysqli\u query（$conn，$sql）；
while（$result=mysqli\u fetch\u assoc（$query））{
$movies[]=$result；
}
$new_movies=array（）；//一种新的数组变量
foreach（$k=>v）{
$array_keys=explode（'，'，$v['Video_title']）；//将Video_title字符串分解为数组
$trimmed_array_key=array_map（'trim'，$array_key）；//从$trimmed_array_key数组的每个值中修剪所有空格
$array_values=explode（“，”，$v['Rating']）；//explode Rating数组
$trimmed_array_values=array_map（'trim'，$array_values）；//从$trimmed_array_values数组中删除所有空格
$new_movies[$v['Username']]=array_combine（$trimmed_array_key，$trimmed_array_value）；//组合$trimmed_array_key数组和$trimmed_array_value数组并分配给相应的用户
}
回声“；打印（新电影）；//打印新阵列
$trimmed\u array\u key=array\u map（'trim'，$array\u key）
将执行以下操作：-
$movies = array();
$sql = "SELECT u.username AS Username, group_concat(v.title) AS Video_title, group_concat(r.rate) AS Rating
FROM `rating` AS r
JOIN `uploads` AS v ON r.video_id = v.vid_id
JOIN `users` as u ON u.user_id = r.rater_id
GROUP by Username" ;
$query = mysqli_query($conn, $sql);
while($result = mysqli_fetch_assoc($query)){
$movies[] = $result;
}
$new_movies = array(); // a new array variable
foreach($movies as $k => $v){
$array_keys = explode(',',$v['Video_title']); // explode Video_title string into array
$trimmed_array_key=array_map('trim',$array_keys); // trim all spaces from each value of $trimmed_array_key array
$array_values = explode(',',$v['Rating']); // explode Rating array
$trimmed_array_values=array_map('trim',$array_values);//remove all spaces from $trimmed_array_values array
$new_movies[$v['Username']] = array_combine($trimmed_array_key,$trimmed_array_values); // combine $trimmed_array_key array and $trimmed_array_values array and assign to corresponding user
}
echo "<pre/>";print_r($new_movies); // print new array
参考资料：-您必须按照以下方式操作：-
$movies = array();
$sql = "SELECT u.username AS Username, group_concat(v.title) AS Video_title, group_concat(r.rate) AS Rating
FROM `rating` AS r
JOIN `uploads` AS v ON r.video_id = v.vid_id
JOIN `users` as u ON u.user_id = r.rater_id
GROUP by Username" ;
$query = mysqli_query($conn, $sql);
while($result = mysqli_fetch_assoc($query)){
$movies[] = $result;
}
$new_movies = array(); // a new array variable
foreach($movies as $k => $v){
$array_keys = explode(',',$v['Video_title']); // explode Video_title string into array
$trimmed_array_key=array_map('trim',$array_keys); // trim all spaces from each value of $trimmed_array_key array
$array_values = explode(',',$v['Rating']); // explode Rating array
$trimmed_array_values=array_map('trim',$array_values);//remove all spaces from $trimmed_array_values array
$new_movies[$v['Username']] = array_combine($trimmed_array_key,$trimmed_array_values); // combine $trimmed_array_key array and $trimmed_array_values array and assign to corresponding user
}
echo "<pre/>";print_r($new_movies); // print new array
$movies=array（）；
$sql=“选择u.username作为用户名，选择group_concat（v.title）作为视频_title，选择group_concat（r.rate）作为评级
从'rating'改为r
在r.video\u id=v.vid\u id上以v的形式加入'uploads'
在u.user\u id=r.rater\u id上以u的身份加入'users'
按用户名分组”；
$query=mysqli\u query（$conn，$sql）；
while（$result=mysqli\u fetch\u assoc（$query））{
$movies[]=$result；
}
$new_movies=array（）；//一种新的数组变量
foreach（$k=>v）{
$array_keys=explode（'，'，$v['Video_title']）；//将Video_title字符串分解为数组
$trimmed_array_key=array_map（'trim'，$array_key）；//从$trimmed_array_key数组的每个值中修剪所有空格
$array_values=explode（“，”，$v['Rating']）；//explode Rating数组
$trimmed_array_values=array_map（'trim'，$array_values）；//从$trimmed_array_values数组中删除所有空格
$new_movies[$v['Username']]=array_combine（$trimmed_array_key，$trimmed_array_value）；//组合$trimmed_array_key数组和$trimmed_array_value数组并分配给相应的用户
}
回声“；打印（新电影）；//打印新阵列
注：-
此行：-$trimmed\u array\u key=array\u map（'trim'，$array\u key）
将执行以下操作：-
$movies = array();
$sql = "SELECT u.username AS Username, group_concat(v.title) AS Video_title, group_concat(r.rate) AS Rating
FROM `rating` AS r
JOIN `uploads` AS v ON r.video_id = v.vid_id
JOIN `users` as u ON u.user_id = r.rater_id
GROUP by Username" ;
$query = mysqli_query($conn, $sql);
while($result = mysqli_fetch_assoc($query)){
$movies[] = $result;
}
$new_movies = array(); // a new array variable
foreach($movies as $k => $v){
$array_keys = explode(',',$v['Video_title']); // explode Video_title string into array
$trimmed_array_key=array_map('trim',$array_keys); // trim all spaces from each value of $trimmed_array_key array
$array_values = explode(',',$v['Rating']); // explode Rating array
$trimmed_array_values=array_map('trim',$array_values);//remove all spaces from $trimmed_array_values array
$new_movies[$v['Username']] = array_combine($trimmed_array_key,$trimmed_array_values); // combine $trimmed_array_key array and $trimmed_array_values array and assign to corresponding user
}
echo "<pre/>";print_r($new_movies); // print new array
参考：-您想要的输出与您得到的完全不同（在索引方面，或者您可以说是列名）。那不是possible@AlivetoDie我并不是真的想让输出与值中的输出完全相同，而是想改变所使用的数组的数量。M.Khalaf检查我的答案，一旦你想要的输出与你得到的完全不同（在索引方面或者你可以说列名方面）。那不是possible@AlivetoDie我不是真的想让输出与值中的输出完全相同，但我正在寻找所用数组数量的变化。M.Khalaf检查我的答案这是我得到的输出：数组（[Mohamed]=>Array（[0]=>Array（[Username]=>Mohamed[Video_title]=>水中的女士，只是我的运气，夜猫子，飞机上的蛇，超人归来，你我和杜普利[Rating]=>3,1.5,3,3.5,5,3.5]，[user1]=>Array（[0]=>Array（[Username]=>user1[Video_title]=>飞机上的蛇，超人归来，夜猫子，水中的女士，只是我的运气，你我和杜普利[Rating]=>3.5,3,2.5,2.5）））阵列上的阵列太多您想要的格式与您得到的完全不同。您建议我改进什么？@M.Khalaf检查我的答案并尝试一下这是我得到的输出：阵列（[Mohamed]=>Array（[0]=>Array（[Username]=>Mohamed[视频标题]=>水中的女士，只是我的运气，夜猫子，飞机上的蛇，超人归来，你我和杜普利[Rating]=>3,1.5,3,3.5,5,3.5]，[user1]=>Array（[0]=>Array（[Username]=>user1[Video_title]=>飞机上的蛇，超人归来，夜猫子，水中的女士，只是我的运气，你我和杜普利[Rating]=>3.5,3,2.5,2.5）））阵列上的阵列太多您想要的格式与您得到的格式完全不同。您建议我改进什么？@M.Khalaf检查我的答案并尝试一下不完全正确这是我现在得到的：阵列（[Mohamed]=>Array（[水中的女士，只是我的运气，夜猫子，飞机上的蛇，超人回来，你我和杜普利]=>3,1.5,3,3.5,5,3.5）[0]=>3,1.5,3,3.5,5,3.5[user1]=>数组（[飞机上的蛇，超人回来，夜猫子，水中的女士，只是我的运气，你我和杜普利]=>3.5,3,2.5,3.5）[1]=>3.5,3.5,3,2.5,3,2.5）从select查询中删除组concat。并使用此代码。不太清楚这是我现在得到的：数组（[Mohamed]=>Array（[Lady in the Water，只是我的运气，夜猫子，蛇