Php 将sql查询转换为Fluentpdo查询
我用php编写了以下sql查询:Php 将sql查询转换为Fluentpdo查询,php,mysql,fluentpdo,Php,Mysql,Fluentpdo,我用php编写了以下sql查询: $query = sprintf("UPDATE bank_info SET amount_dollar = amount_dollar +'$amount_dollar' , amount_euro = amount_euro + '$amount_euro' , amount_local = amount_local + '$
$query = sprintf("UPDATE bank_info SET
amount_dollar = amount_dollar +'$amount_dollar' ,
amount_euro = amount_euro + '$amount_euro' ,
amount_local = amount_local + '$amount_local'
WHERE bank_id = '$bank_id' ");
此查询工作正常,但我想使用FluentPDO转换此查询。
我想使用数组来设置值。
例如:
$table='bank_info'; //table name
$arrVal=array(); //values needs to be SET
$arrVal['amount_dollar = amount_dollar+?']=$amount_dollar;
$arrVal['amount_euro = amount_euro+?']=$amount_euro;
$arrVal['amount_local = amount_local+?']=$amount_local;
$arrWhere=array(); //where condition
$arrWhere['bank_id']=$bank_id;
以下是查询:
$query = $this->pdo->update($table)->set($arrVal)->where($arrWhere);
$query->execute();
我认为问题出在$arrVal中,找不到正确的方法来设置表中某列的当前值并向其添加值。
我多次使用数组从DB/表中选择和获取值,因此我认为$arrhere不是问题所在 嗯,找到了答案 例如: 这对我有用:
$id = 5;
$field = 'stock';
$amount = 1;
$increment = array($field => new FluentLiteral($field.' + '.$amount));
$fpdo->update('products')->set($increment)->where('id', $id)->execute();