Php 通过链接传递多个变量（仅读取一个）

我试图从链接中传递一些变量，但出于某种原因，它只读取其中一个变量。下面是链接和代码。roundNo表现得很好

archery/viewround.php？gameNo=1&roundNo=7

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你检查了打印请求了吗？对我来说没问题。在echo？DB连接之前，您有什么声明？但我仍然放在文件顶部，但仍然没有显示。是否尝试打印？\r$\u请求显示数组[roundNo]=>10，然后以PHPSSID等开头…尝试archery/viewround.php？&gameNo=1&roundNo=7和archery/viewround.php？roundNo=7&gameNo=1，并让我们知道您看到了什么。

    echo $_GET['gameNo'];
    echo $_GET['roundNo'];
  echo "<table border><tr><th>Round ID</th><th>Match Name</th><th>Player Name</th><th>Shot 1</th><th>Shot 2</th><th>Shot 3</th><th>Shot 4</th><th>Shot 5</th><th>Shot 6</th><th>Shot 7</th><th>Shot 8</th><th>Shot 9</th><th>Shot 10</th></tr>";
  while ($row = mysql_fetch_array($sql)) {
    $tempPlayerName = getnamewithid($row["player_id"]);
    $tempMatchName = getmatchnamewithid($_GET['gameNo']);
    echo "<tr>";
    echo '<td>' . $row["round_id"].'</td>';
    echo "<td>" . $tempMatchName. "</td>";
    echo "<td>" . $tempPlayerName. "</td>"; 
    echo "<td>" . $row["shot_1"] . "</td>";
    echo "<td>" . $row["shot_2"] . "</td>";
    echo "<td>" . $row["shot_3"] . "</td>";
    echo "<td>" . $row["shot_4"] . "</td>";
    echo "<td>" . $row["shot_5"] . "</td>";
    echo "<td>" . $row["shot_6"] . "</td>";
    echo "<td>" . $row["shot_7"] . "</td>";
    echo "<td>" . $row["shot_8"] . "</td>";
    echo "<td>" . $row["shot_9"] . "</td>";
    echo "<td>" . $row["shot_10"] . "</td>";
    echo "</tr>";
    $i++;
  }
  echo "</table>";