Php 如何从WP_Post对象获取标题
我试图查看子页面名称列表,其中包含一些要显示的描述。我使用下面的代码Php 如何从WP_Post对象获取标题,php,wordpress,foreach,Php,Wordpress,Foreach,我试图查看子页面名称列表,其中包含一些要显示的描述。我使用下面的代码 $my_wp_query = new WP_Query(); $all_wp_pages = $my_wp_query->query(array('post_type' => 'page')); // Get the page as an Object $portfolio = get_page_by_title('service'); // Filter through all pages and find P
$my_wp_query = new WP_Query();
$all_wp_pages = $my_wp_query->query(array('post_type' => 'page'));
// Get the page as an Object
$portfolio = get_page_by_title('service');
// Filter through all pages and find Portfolio's children
$portfolio_children = get_page_children( $portfolio->ID, $all_wp_pages );
// echo what we get back from WP to the browser
echo "<pre>";print_r(
);
foreach($portfolio_children as $pagedet):
echo $pagedet['post_title'];
endforeach;
在foreach之后如果我打印$pagedet我得到
<?php
$my_wp_query = new WP_Query();
$all_wp_pages = $my_wp_query->query(array('post_type' => 'page', 'posts_per_page' => -1));
$childpg = get_page_children(8, $all_wp_pages);
foreach($childpg as $children){
$page = $children->ID;
$page_data = get_page($page);
$content = $page_data->post_content;
$content = $page_data->the_title;
$content = apply_filters('the_content',$content);
$content = str_replace(']]>', ']]>', $content);
echo '<div class="row-fluid"><span class="span4">';
echo get_the_post_thumbnail( $page );
echo '</span><span class="span8">'.$content.'</span></div>';
}
?>
我试着打电话给$pagedet['post_title'],但id没有显示任何内容…提前谢谢这是从我的笔记中得知的,我正在处理您的确切情况。希望能有帮助
$page_data->post_content //is true,
$page_data->the_title // is false.
为了确保这一点,您应该使用每页数据作为列名 比如说,
<?php
$post = get_post($_GET['id']);
$post->post_title;
?>
试试这个。给出正确的想法
foreach($portfolio_children as $pagedet) {
替换上面的foreach: 将对象数组([0]、[1]、[2]…)设置为$pagedet的单个实例
$post_title = $pagedet->post_title;
现在创建变量$post_title,使其等于数组中每个对象的“post_title”值
echo $pagedet[0]->post_title;
echo $pagedet[1]->post_title;
echo $pagedet[2]->post_title;
这在技术上是可行的,但您希望以编程方式循环遍历每个实例,而不标识数组中的每个对象
echo $post_title;
};
现在您可以写出每个帖子的标题值:
foreach($portfolio_children as $pagedet) {
$post_title = $pagedet->post_title;
echo $post_title;
};
总之
您使用的是关联数组表示法,而不是对象表示法。您应该调用:
$pagedet->post_title
在循环中尝试此echo$pagedet->post_title
echo $post_title;
};
foreach($portfolio_children as $pagedet) {
$post_title = $pagedet->post_title;
echo $post_title;
};