Php 搜索字符串中的单词并基于另一个字符串拆分连接的字符串

我如何在php中执行以下操作

我有两个输入$bankdata和$databasedata

问题：

如果单词与其他字符串单词匹配，则将其拆分为字符串

具有更多空格的字符串将被视为基本字符串，在下面的情况下，$databasedata将被视为基本字符串，然后它将与每个单词的$bankdata进行比较，然后拆分

DHANA

和

LAKSHMI

，然后重写

$bankdata = DHANA LAKSHMI K

例如：

Input :  
 $bankdata      = 'DHANALAKSHMI  K' 
 $databasedata  = 'DHANA LAXMI KOILADA'

Output :  
 $bankdata      = 'DHANA LAKSHMI  K'  //This willchanged
 $databasedata  = 'DHANA LAXMI KOILADA'

Input : 
 $bankdata      = 'P VENKATESWARA RAO' 
 $databasedata  = 'PARELLA VENKATESWARARAO'

Output :  
 $bankdata      = 'P VENKATESWARA RAO' 
 $databasedata  = 'PARELLA VENKATESWARA RAO' //This willchanged

Input : 
 $bankdata      = 'LINGAREDDY S' 
 $databasedata  = 'LINGA REDDY SHEELAM'

Output :  
 $bankdata      = 'LINGA REDDY S'   //This will changed 
 $databasedata  = 'LINGA REDDY SHEELAM'

Input : 
 $bankdata      = 'ROSHAN LAL' 
 $databasedata  = 'ROSHANLAL X'

Output :  
 $bankdata      = 'ROSHAN LAL' 
 $databasedata  = 'ROSHAN LAL X' //This will changed

---

Hello@daootim此代码将检查另一个字符串中的单词，并将其替换为额外的空格。你需要创造更多的条件，因为这是非常直接的。我希望有帮助

$bankdata      = 'P VENKATESWARARAO RAO' ;
$databasedata  = 'PARELLA VENKATESWARARAORAO';
echo 'INPUT: ' . $databasedata . '<br>';
echo 'INPUT: ' . $bankdata . '<br>';
$inputArray1 = explode(' ',$bankdata);
$inputArray2 = explode(' ',$databasedata);

foreach ($inputArray1 as $word) {
    if (strlen($word) > 1){
        foreach ($inputArray1 as $reference) {
            if ($reference != $word){
                if (strpos($reference,$word) > 0) continue 2;
            }
        }
        $databasedata = str_replace($word, $word." ",$databasedata);
    }
}
foreach ($inputArray2 as $word) {
    if (strlen($word) > 1){
        foreach ($inputArray2 as $reference) {
            if ($reference != $word){
                if (strpos($reference,$word) > 0) continue 2;
            }
        }
        $bankdata = str_replace($word, $word." ",$bankdata);
    }
}
echo 'OUTPUT: ' . $databasedata . '<br>';
echo 'OUTPUT: ' . $bankdata . '<br>';

$bankdata='P venkateswarao RAO'；
$databasedata='PARELLA VENKATESWARARAORAO'；
回显“输入：”$数据库数据。”
'；
回显“输入：”$银行数据。”
'；
$inputArray1=爆炸（“”，$bankdata）；
$inputArray2=爆炸（“”，$databasedata）；
foreach（$word形式的inputArray1）{
如果（strlen（$word）>1）{
foreach（$inputArray1作为$reference）{
如果（$reference！=$word）{
如果（strpos（$reference，$word）>0）继续2；
}
}
$databasedata=str_replace（$word，$word.“，$databasedata）；
}
}
foreach（$word形式的inputArray2）{
如果（strlen（$word）>1）{
foreach（$inputArray2作为$reference）{
如果（$reference！=$word）{
如果（strpos（$reference，$word）>0）继续2；
}
}
$bankdata=str_replace（$word，$word.“，$bankdata）；
}
}
回显“输出：”$数据库数据。”
'；
回显“输出：”$银行数据。”
'；

输入：PARELLA VENKATESWARARAORAO

输入：p VENKATESWARARAORAO

产出：PARELLA Venkateswarao RAO

<?php

function swap(&$bankdata, &$databasedata)
{
    // get the spaces from each word
    // we use preg_replace to remove additional spaces in any of the words.
    $bank_arr = explode(' ', preg_replace('/\s+/', ' ', $bankdata));
    $data_arr = explode(' ' , preg_replace('/\s+/', ' ', $databasedata));

    $bank_space_count = count($bank_arr);
    $data_space_count = count($data_arr);

    $fixUp = function ($words, $with)
    {
        $patterns = [];
        $replacements = [];
        foreach($with as $each_word) {
            // skip single characters
            if (strlen($each_word) == 1) {
                continue;
            }

            $patherns[] = "/{$each_word}(\w\s+)?/";
            $replacements[] = "$0 ";
        }

        return preg_replace($patherns, $replacements, $words);
    };


    if ($bank_space_count >= $data_space_count) {
        $databasedata = $fixUp($databasedata, $bank_arr);
    }
    else {
        $bankdata = $fixUp($bankdata, $data_arr);
    }
}

$bankdata      = 'DHANALAKSHMI  K';
$databasedata  = 'DHANA LAXMI KOILADA';

swap($bankdata, $databasedata);


var_dump($bankdata, $databasedata);

---

输出：p Venkateswarao RAO

当我通过'DB INPUT:VARUN SURYAKANT LLOYD BANK INPUT:SURYA VARU LLOYD DB OUTPUT:VARU N SURYA KANT LLOYD。银行输出：SURYA VARU LLOYD`问题是VARUN在VARU N中得到了拆分，而这不应该拆分代码，因为代码按预期工作。在银行输入中，你有单词VARU.ok你是对的，
$dbdata=GAURE LAL AHIRWAR，$bankdata=GORELAL AHIRWAR
输出-
$bankdata=GORE LAL AHIRWAR
$dbdata=M DEEPA，$bankdata=M DEEPA
，$bankdata=M DEEPA你能建议我关闭答案吗？如果（strlen（$word）>1）

这会起作用吗？当我通过

数据库输入：RAJARANI MOHANRAO，银行输入：RAJA MOHAN

将输出作为

数据库输出：RAJARANI MOHANRAO，银行输出：RAJA MOHAN

预期输出DB输出是RAJA RANI MOHAN RAO你能帮我吗

<?php

function swap(&$bankdata, &$databasedata)
{
    // get the spaces from each word
    // we use preg_replace to remove additional spaces in any of the words.
    $bank_arr = explode(' ', preg_replace('/\s+/', ' ', $bankdata));
    $data_arr = explode(' ' , preg_replace('/\s+/', ' ', $databasedata));

    $bank_space_count = count($bank_arr);
    $data_space_count = count($data_arr);

    $fixUp = function ($words, $with)
    {
        $patterns = [];
        $replacements = [];
        foreach($with as $each_word) {
            // skip single characters
            if (strlen($each_word) == 1) {
                continue;
            }

            $patherns[] = "/{$each_word}(\w\s+)?/";
            $replacements[] = "$0 ";
        }

        return preg_replace($patherns, $replacements, $words);
    };


    if ($bank_space_count >= $data_space_count) {
        $databasedata = $fixUp($databasedata, $bank_arr);
    }
    else {
        $bankdata = $fixUp($bankdata, $data_arr);
    }
}

$bankdata      = 'DHANALAKSHMI  K';
$databasedata  = 'DHANA LAXMI KOILADA';

swap($bankdata, $databasedata);


var_dump($bankdata, $databasedata);