Php 使用简单的HTML DOM解析器来解析JSON?
我正试图将一个被刮掉的网站的每个元素分组,将其转换为一个json元素,但它似乎不起作用Php 使用简单的HTML DOM解析器来解析JSON?,php,json,html-parsing,Php,Json,Html Parsing,我正试图将一个被刮掉的网站的每个元素分组,将其转换为一个json元素,但它似乎不起作用 <?php // Include the php dom parser include_once 'simple_html_dom.php'; header('Content-type: application/json'); // Create DOM from URL or file $html = file_get_html('urlhere'); foreach($html-&
<?php
// Include the php dom parser
include_once 'simple_html_dom.php';
header('Content-type: application/json');
// Create DOM from URL or file
$html = file_get_html('urlhere');
foreach($html->find('hr ul') as $ul)
{
foreach($ul->find('div.product') as $li)
$data[$count]['products'][]['li']= $li->innertext;
$count++;
}
echo json_encode($data);
?>
如何去除所有冗余信息,并命名重新格式化的json中的每个元素
谢谢 您只需在内部循环中扩展逻辑:
foreach($html->find('hr ul') as $ul)
{
foreach($ul->find('div.product') as $li) {
$product = array();
$product['link'] = $li->find('a.th')[0]->href;
$product['name'] = trim($li->find('div.name a')[0]->innertext);
$product['subtitle'] = trim($li->find('div.subtitle')[0]->innertext);
$product['image'] = explode("'", $li->find('div')[0]->style)[1];
$data[$count]['products'][] = $product;
}
}
echo json_encode($data);
我可以问一下如何删除“产品”前面的“{”“:{”:[{“链接”:…?只需将
$data[$count]['products'][]=$product;
更改为$data['products'][]=$product;
您是最好的。谢谢您的帮助!:)
{"products":[{
"link":"/products/56942-haters-crewneck-sweatshirt",
"image":"http://s0.com/images/15814/v600_B_AltApparel_Crew.png",
"name":"Haters Crewneck Sweatshirt",
"subtitle":"60.00"}
]}
foreach($html->find('hr ul') as $ul)
{
foreach($ul->find('div.product') as $li) {
$product = array();
$product['link'] = $li->find('a.th')[0]->href;
$product['name'] = trim($li->find('div.name a')[0]->innertext);
$product['subtitle'] = trim($li->find('div.subtitle')[0]->innertext);
$product['image'] = explode("'", $li->find('div')[0]->style)[1];
$data[$count]['products'][] = $product;
}
}
echo json_encode($data);