将现有php搜索和重构转换为OOP

大家新年快乐

我有我刚开始编写的php代码，我想知道是否有一种方法可以使它成为OOP，或者是否应该找到另一种方法来重新创建它。欢迎所有意见

<?php
require("local_php.inc");
DatabaseConnect();

//Variables to post to results.php

$keyword=$_POST['keyword'];
$location=$_POST['location'];
$type=$_POST['type'];

//Query

$q1 = "SELECT ssearch.id, ssearch.Company, ssearch.Address, ssearch_state.state_location, ssearch.City, ssearch.Zip, ssearch.Phone, ssearch.Description, ssearch.Email, 
ssearch_event.Event_name FROM 

(ssearch LEFT OUTER JOIN ssearch_state ON ssearch.State = ssearch_state.id) 

LEFT OUTER JOIN  ssearch_event ON ssearch.Event_id = ssearch_event.id 

WHERE ssearch.Company LIKE '%$keyword%'";

if($location != "all")
{
 $q1 .= "AND ssearch_state.state_location ='$location' "; 
}
if($type != "all")
{
 $q1 .= "AND ssearch_event.Event_name ='$type' "; 
}
$q1 .= "ORDER BY ssearch.Company DESC LIMIT 0, 3;";
$result = mysql_query($q1);
$q1_total_rows = mysql_num_rows($result);

?>
<div id="content"> 
 <?php if($q1_total_rows >= 1) { ?>
 <?php while ($record = mysql_fetch_assoc($result)) { ?>
 <div id="table">
  <table width="379" height="64" border="0" align="left" bordercolor="#FFFF00" bgcolor="#FEFFD5">
   <tr>
    <td width="187"><p align="center" class="contentfontsmallsearch"><a href="display.php?ID=<?php echo $record["id"];?>"><?php echo $record["Company"];?></a></p></td>
    <td width="182"><p align="center" class="contentfontsmallsearch"><?php echo $record["Event_name"];?></p></td>
   </tr>
   <tr>
    <td><p align="center" class="contentfontsmallsearch"><?php echo $record["state_location"];?></p></td>
    <td><p align="center" class="contentfontsmallsearch"><?php echo $record["Description"];?></p></td>
   <tr>
  </table>
 </div>
 <?php } ?>
 <? } else { ?>
 <div id="table2">
 <h3 align="center" class="noresults">No Results</h3><br />
 <p align="center" class="contentfontsmallsearch">Please Try your Search Again</p><br />
 <form action="results.php" method="post" name="myform" id="myform">
  <table width="379" height="190" border="0" align="left" bordercolor="#FFFF00" bgcolor="#FEFFD5">
   <tr>
    <td width="143"><p align="center" class="contentfontsmallsearch">Keyword</p></td>
    <td width="226">
     <label>
       <input name="keyword" type="text" id="keyword" size="30" />
     </label>
    </td>
   </tr>
   <tr>
    <td><p align="center" class="contentfontsmallsearch">Location</p></td>
    <td>
     <select name="location">
       <option value="all" selected="selected">All Locations</option>
       <option value="Pennsylvania">Pennsylvania</option>
       <option value="New Jersey">New Jersey</option>
       <option value="Delaware">Delaware</option>
     </select>
    </td>
   <tr>
    <td width="143"><p align="center" class="contentfontsmallsearch">Event Type </p></td>
    <td>
     <select name="type">
       <option value="all" selected="selected">All Events</option>
       <option value="Rally Event">Rally Event</option>
       <option value="Awareness Event">Awareness Event</option>
       <option value="Donation Event">Donation Event</option>
     </select>
    </td>
   </tr>
   <tr>
    <td></td>
    <td><input type="submit" name="Submit2" value="Search" /></td>
   </tr>
  </table>
 </form>
 </div>
 <? } ?>
</div>

---

我更希望您先确保安全。读取
$\u POST
输入变量时，添加
mysql\u real\u escape\u字符串。现在，您的代码完全依赖于magic_引号

作为第二步，您可以将此代码程序化。设计一个
location\u query（）。我看不出有什么直接的结构会有利于跳转到“使其面向对象”上来。
你想要重写它的尖锐原因是什么？但有一件事你应该紧急解决，那就是第一步，放弃使用mysql_*函数，mysqli_*支持程序和OO@Pekka我只是觉得它看起来太初级了。另外，在我知道SQL注入之前，这是我在大学里做的事情。