使用PHP从PostgreSQL获取所选列的元信息
在PHP中,有没有一种方法可以获取postgre结果中每个列的表名 假设您有一个带有连接的select,例如:使用PHP从PostgreSQL获取所选列的元信息,php,postgresql,Php,Postgresql,在PHP中,有没有一种方法可以获取postgre结果中每个列的表名 假设您有一个带有连接的select,例如: $Q = <<<E2OD SELECT * FROM user U LEFT JOIN department D ON U.department_id = D.id E2OD; 返回 Array ( [0] => id [name] => id [1] => id [alias] => id
$Q = <<<E2OD
SELECT * FROM user U
LEFT JOIN department D ON U.department_id = D.id
E2OD;
返回
Array
(
[0] => id
[name] => id
[1] => id
[alias] => id
[2] => user
[relation] => user
[3] => 8
[length] => 8
[4] => BIGINT
[type] => BIGINT
)
Array
(
[pgsql:oid] => 20
[native_type] => int8
[name] => id
[len] => 8
[precision] => -1
[pdo_type] => 2
)
在PHP/PostgreSQL中:
$select = $DB->query($Q);
$meta = $select->getColumnMeta(0);
返回
Array
(
[0] => id
[name] => id
[1] => id
[alias] => id
[2] => user
[relation] => user
[3] => 8
[length] => 8
[4] => BIGINT
[type] => BIGINT
)
Array
(
[pgsql:oid] => 20
[native_type] => int8
[name] => id
[len] => 8
[precision] => -1
[pdo_type] => 2
)
如您所见,没有关于该列所来自的表的信息。显示表名时缺少键[relation]=>user
或类似项
PHP可以通过它的PG或PDO库获得这些信息吗?PostgreSQL是否向客户端库提供此信息?要做到这一点,需要做些什么
谢谢你的提示
迈克尔检查。谢谢你,弗兰克。我搜索了手册,但没找到。原来我的本地.chm帮助文件几乎是最新的,但是。。。有点过时:)