Php 为什么我会犯这个错误？他们的东西我应该换吗？

我想将我的值传递给salesforce api。我正在提取贷款申请编号，正如您在最后一行错误中看到的那样。但它也显示“状态为200时失败”。他们的代码是否需要更改，或者拥有它就可以了。我还想在前端显示贷款申请编号。它的语法是什么。我已经尝试过php的数组语法，但它不起作用。错误如下

Error: call to URL https://cs31.salesforce.com/services/apexrest/CreateLoan/ failed with status 200, response HTTP/1.1 200 OK Date: Tue, 01 Mar 2016 12:31:56 GMT Set-Cookie: BrowserId=cLMf4KPnTvqxcif286fSRQ;Path=/;Domain=.salesforce.com;Expires=Sat, 30-Apr-2016 12:31:56 GMT Expires: Thu, 01 Jan 1970 00:00:00 GMT Content-Type: application/json;charset=UTF-8 Transfer-Encoding: chunked "success: Loan Application Number - 804326966", curl_error , curl_errno 0

<?php session_start();
$json=$_SESSION['json'];
$details=json_decode($json);
//var_dump($details);
$name='LoanCreationService';
$instance_url='https://cs31.salesforce.com/services/apexrest/CreateLoan/';
$access_token = $details->{'access_token'};
$message=create_account($name, $instance_url, $access_token);
//echo $message->{'message'};
function create_account($name, $instance_url, $access_token) {
    $url = $instance_url;
    //$content = json_encode(array("Name" => $name));
    $content=$_SESSION['content'];;
    //echo $content;
    $curl = curl_init($url);
    curl_setopt($curl, CURLOPT_HEADER, true);
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($curl, CURLOPT_HTTPHEADER,
            array("Authorization: OAuth $access_token",
                "Content-type: application/json"));
    curl_setopt($curl, CURLOPT_POST, true);
    curl_setopt($curl, CURLOPT_POSTFIELDS, $content);

    $json_response = curl_exec($curl);
    //echo $json_response;
    $status = curl_getinfo($curl, CURLINFO_HTTP_CODE);

    if ( $status != 201 ) {
        die("Error: call to URL $url failed with status $status, response $json_response, curl_error " . curl_error($curl) . ", curl_errno " . curl_errno($curl));
    }

    //echo "HTTP status $status creating account<br/><br/>";

    curl_close($curl);

    $response = json_decode($json_response, true);

    echo $id = $response["id"];



    return $id;
}
?>

我的代码如下

Error: call to URL https://cs31.salesforce.com/services/apexrest/CreateLoan/ failed with status 200, response HTTP/1.1 200 OK Date: Tue, 01 Mar 2016 12:31:56 GMT Set-Cookie: BrowserId=cLMf4KPnTvqxcif286fSRQ;Path=/;Domain=.salesforce.com;Expires=Sat, 30-Apr-2016 12:31:56 GMT Expires: Thu, 01 Jan 1970 00:00:00 GMT Content-Type: application/json;charset=UTF-8 Transfer-Encoding: chunked "success: Loan Application Number - 804326966", curl_error , curl_errno 0

<?php session_start();
$json=$_SESSION['json'];
$details=json_decode($json);
//var_dump($details);
$name='LoanCreationService';
$instance_url='https://cs31.salesforce.com/services/apexrest/CreateLoan/';
$access_token = $details->{'access_token'};
$message=create_account($name, $instance_url, $access_token);
//echo $message->{'message'};
function create_account($name, $instance_url, $access_token) {
    $url = $instance_url;
    //$content = json_encode(array("Name" => $name));
    $content=$_SESSION['content'];;
    //echo $content;
    $curl = curl_init($url);
    curl_setopt($curl, CURLOPT_HEADER, true);
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($curl, CURLOPT_HTTPHEADER,
            array("Authorization: OAuth $access_token",
                "Content-type: application/json"));
    curl_setopt($curl, CURLOPT_POST, true);
    curl_setopt($curl, CURLOPT_POSTFIELDS, $content);

    $json_response = curl_exec($curl);
    //echo $json_response;
    $status = curl_getinfo($curl, CURLINFO_HTTP_CODE);

    if ( $status != 201 ) {
        die("Error: call to URL $url failed with status $status, response $json_response, curl_error " . curl_error($curl) . ", curl_errno " . curl_errno($curl));
    }

    //echo "HTTP status $status creating account<br/><br/>";

    curl_close($curl);

    $response = json_decode($json_response, true);

    echo $id = $response["id"];



    return $id;
}
?>

您正在代码中终止它，因为您查找的状态是201，请求返回200，正如您在返回的错误消息中所看到的那样。如果需要，尝试将状态设置为201。

状态200 OK，表示您的请求已成功，并且您已经获得了

“成功：贷款申请号-804326966”

。见

也许你可以试试这个

$json_response = curl_exec($curl);
    //echo $json_response;
    $status = curl_getinfo($curl);

if ($output === false || $status ['http_code'] != 200) {
  $output = "No cURL data returned for $url [". $status ['http_code']. "]";
  if (curl_error($curl))
    $output .= "\n". curl_error($curl);
  }
//now check the resopose

 var_dump($json_response);
    //echo "HTTP status $status creating account<br/><br/>";
    $key = "success: Loan Application Number -";
    $pos = strpos($json_response, $key);
    //echo $pos;
    $appNumber = substr($json_response,strlen($key)+ $pos,strlen($json_response));  
    echo $appNumber;
    curl_close($curl);
    $response = json_decode($json_response, true);

echo $id = $response["id"];

$json\u response=curl\u exec（$curl）；
//echo$json_响应；
$status=curl\u getinfo（$curl）；
如果（$output==false | |$status['http_code']！=200）{
$output=“没有为$url[”$status['http_code']。“]”返回cURL数据；
if（curl_错误（$curl））
$output.=“\n”.curl\u错误（$curl）；
}
//现在检查一下姿势
var_dump（$json_响应）；
//回显“HTTP状态$status创建帐户

”；
$key=“成功：贷款申请编号-”；
$pos=strpos（$json\u响应，$key）；
//echo$pos；
$appNumber=substr（$json_响应，strlen（$key）+$pos，strlen（$json_响应））；
echo$appNumber；
curl_close（$curl）；
$response=json\u decode（$json\u response，true）；
echo$id=$response[“id”]；

感谢您的回复。你能告诉我如何从整个回复中只获取贷款申请号吗。