Php 从空值laravel创建默认对象

我从空值laravel创建默认对象时遇到了一个错误

，我成功地用下面的代码插入了新行，但今天当我尝试测试代码时，它返回的错误指向行
$revow->rating=$request->productrating

my db表的结构是：

id | fname | lname | email |国家|标题|内容|评级|缩略图|巡演| id |状态

    public function store(Request $request)
{
    // dd($request->all());
    $this->validate($request, [
        'fname'     => 'required',
        'lname'     =>  'required',
        'email'     => 'required',
        'country'   => 'required',
        'title'   => 'required|min:10',
        'productrating' => 'required',
        'content'   => 'required|min:10'
        ]);        
    // dd($request->productrating);
    $review = new Review;
    $review->fname = $request->fname;
    $review->lname = $request->lname;
    $review->email = $request->email;
    $review->country = $request->country;
    $review->title = $request->title;
    $review->content = $request->content;        
    $reviw->rating = $request->productrating;
    if($request->hasFile('fileupload1')){
        $image = $request->file('fileupload1');
        $filename = 'thumb'.time().'.'.$image->getClientOriginalExtension();
        $location = 'images/client_review/'.$filename;
        Image::make($image)->resize(200, 200)->save($location);
        $review->thumbnail = $location;
    }
    $review->tour_id = $request->product_id;
    $review->status = false;
    $review->save();
    Session::flash('success','Thank You for submitting us your review.');
    return view('public.pages.message-review');        
}

我正在从表单发送以下数据以保存到表中。
您在
$revow->rating=$request->productrating中有一个错误将
$review
更改为
$review
，它将起作用
我认为您需要更新代码，如下所示：

    $review = new Review;
    $review->fname = $request->fname;
    $review->lname = $request->lname;
    $review->email = $request->email;
    $review->country = $request->country;
    $review->title = $request->title;
    $review->content = $request->content;        
    $review->rating = $request->productrating;