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Php 单联接列问题的Symfony关联_Php_Symfony_Doctrine Orm_Doctrine_Symfony Forms - Fatal编程技术网

Php 单联接列问题的Symfony关联

Php 单联接列问题的Symfony关联,php,symfony,doctrine-orm,doctrine,symfony-forms,Php,Symfony,Doctrine Orm,Doctrine,Symfony Forms,我有以下代码定义两个实体之间的关系: /** * Barcode * * @ORM\Table(name="barcode") * @ORM\Entity */ class Barcode { . . . /** * @var ArrayCollection * * @ORM\ManyToMany(targetEntity="Entity\Product", cascade={"persist"}

我有以下代码定义两个实体之间的关系:

/**
 * Barcode
 *
 * @ORM\Table(name="barcode")
 * @ORM\Entity
 */
class Barcode
{
.
.
.
/**
     * @var ArrayCollection
     *
     * @ORM\ManyToMany(targetEntity="Entity\Product", cascade={"persist"}, mappedBy="barcodes")
     */
    protected $products;
.
.
.

  /**
     * Barcode constructor.
     */
    function __construct()
    {
        $this->products = new ArrayCollection();
    }

使用xml文件中定义的关系:

 <many-to-many field="barcodes" target-entity="Entity\Barcode"
                      inversed-by="products" index-by="products" fetch="LAZY">
            <cascade>
                <cascade-persist/>
            </cascade>
            <join-table name="products_barcodes">
                <join-columns>
                    <join-column name="product_id" referenced-column-name="id"/>
                </join-columns>
                <inverse-join-columns>
                    <join-column name="barcode_id" referenced-column-name="id" nullable="1"/>
                </inverse-join-columns>
            </join-table>
        </many-to-many>

执行任何查询时,我都会遇到以下错误: “实体\条形码#产品”不是与单个联接列的关联。

有什么问题吗?

注意:在产品类的表单中添加需要查询生成器属性的项时发现问题

 <many-to-many field="barcodes" target-entity="Entity\Barcode"
                      inversed-by="products" index-by="products" fetch="LAZY">
            <cascade>
                <cascade-persist/>
            </cascade>
            <join-table name="products_barcodes">
                <join-columns>
                    <join-column name="product_id" referenced-column-name="id"/>
                </join-columns>
                <inverse-join-columns>
                    <join-column name="barcode_id" referenced-column-name="id" nullable="1"/>
                </inverse-join-columns>
            </join-table>
        </many-to-many>