在php中打印特定的xml节点值
我有以下XML文件在php中打印特定的xml节点值,php,xml,Php,Xml,我有以下XML文件 <study> <participant name="Jone" gender="male" nationality="Canadian" job="web developer" country="Canada" years="2"/> <scenario_1> <s1_first name="drieseng">Scenario 1 first developer</s1_first>
<study>
<participant name="Jone" gender="male" nationality="Canadian" job="web developer" country="Canada" years="2"/>
<scenario_1>
<s1_first name="drieseng">Scenario 1 first developer</s1_first>
<s1_second name="Scott Hernandez">Scenario 1 2nd developer</s1_second>
<s1_third name="Ryan Boggs">Scenario 1 3rd developer</s1_third>
<s1_forth name="Ian MacLean">Scenario 1 4th developer</s1_forth>
<s1_fifth name="Michael C. Two">Scenario 1 5th developer</s1_fifth>
</scenario_1>
<scenario_2>
<s2_first name="Charles Chan">Scenario 2 1st developer</s2_first>
<s2_second name="Charles Chan">Scenario 2 2nd developer</s2_second>
<s2_third name="drieseng">Scenario 2 3rd developer</s2_third>
<s2_forth name="claytonharbour">Scenario 2 4th developer</s2_forth>
<s2_fifth name="Hala Dajani">Scenario 2 4th developer</s2_fifth>
</scenario_2>
<scenario_3>
<s3_first name="Michael C. Two">Scenario 3 1st developer</s3_first>
<s3_second name="Giuseppe Greco">Scenario 3 2nd developer</s3_second>
<s3_third name="Ian MacLean">Scenario 3 3rd developer</s3_third>
<s3_forth name="Gregory Goltsov">Scenario 3 4th developer</s3_forth>
<s3_fifth name="Michael C. Two">Scenario 3 5th developer</s3_fifth>
</scenario_3>
</study>
它完美地打印属性,但不打印值。如何修复它,使其同时打印节点的值?每个SimpleXMLElement都有一个属性
innerNode
。将其转换为字符串,它将是您正在寻找的值。您非常接近,但是使用SimpleXML没有->nodeValue
属性,只需将元素对象转换为字符串即可:
echo $scenario_2_developer['name'], ": ", $scenario_2_developer, "\n";
^
|
echo casts this object to string
但我真的很想知道是谁创建了这样一个XML,以这种方式对元素名称进行编号似乎适得其反。XML应该是固定的,以便更好地使用。您介意编写代码吗?我不明白你的意思
echo $scenario_2_developer['name'], ": ", $scenario_2_developer, "\n";
^
|
echo casts this object to string