我希望从数据库中以表格数据形式获取和显示图像,而不是以crud中的图像标题形式,但无法在php codeigniter中预览图像
模态窗体和按钮代码(视图文件) fetch函数的模态代码我希望从数据库中以表格数据形式获取和显示图像,而不是以crud中的图像标题形式,但无法在php codeigniter中预览图像,php,jquery,ajax,codeigniter,Php,Jquery,Ajax,Codeigniter,模态窗体和按钮代码(视图文件) fetch函数的模态代码 public function FetchCoach() { $query = $this->db->get('coach'); if(count($query->result() ) > 0) { return $query->result(); } } 我不想使用dataTable jquery
public function FetchCoach()
{
$query = $this->db->get('coach');
if(count($query->result() ) > 0)
{
return $query->result();
}
}
我不想使用dataTable jquery语法,如果可能的话,请在没有dataTable的情况下帮助我,或者尽量少编辑上面的代码。提前感谢。您能提供有关您的数据库的更多信息吗?您是否以blob格式/文本/其他格式保存图像?请检查图像@kirbare您是否以url/base64保存图像?否,先生,您可以看到上面提到的数据库结构图像@kirbe
<table class="table table-bordered table-hover">
<thead>
<tr>
<th>ID</th>
<th>Coach Image</th>
<th>Coach Type</th>
<th>Coach Name</th>
<th>Coach Designation</th>
<th>Coach Location</th>
<th>Coach Description</th>
<th>Action</th>
</tr>
</thead>
<tbody id="tbody"></tbody>
</table>
function fetch(){
$.ajax({
url:"<?php echo base_url(); ?>FetchCoach",
type: "post",
dataType: "json",
success:function(data)
{
//console.log(data);
var tbody = "";
var i = "1";
for(var key in data){
tbody += "<tr>";
tbody += "<td>"+ i++ + "</td>";
tbody += "<td>"+ data[key]['coach_img'] + "</td>";
tbody += "<td>"+ data[key]['coach_type'] + "</td>";
tbody += "<td>"+ data[key]['coach_name'] + "</td>";
tbody += "<td>"+ data[key]['coach_designation'] + "</td>";
tbody += "<td>"+ data[key]['coach_location'] + "</td>";
tbody += "<td>"+ data[key]['coach_description'] + "</td>";
tbody += `<td>
<a href = "#" id="delete_data" class="btn btn-sm btn-outline-danger" value="${data[key]['coach_id']}"><i class="fas fa-trash-alt"></i></a>
<a href = "#" id="edit_data"class="btn btn-sm btn-outline-info" value="${data[key]['coach_id']}"><i class="fas fa-edit"></i></a>
</td>`
tbody += "</tr>";
}
$("#tbody").html(tbody);
}
});
}
fetch();
public function FetchCoach()
{
if($this->session->userdata('email')=="" && $this->session->userdata('password')=="")
{
$this->load->view('Admin/index');
}
else
{
if($this->input->is_ajax_request())
{
$posts = $this->adm->FetchCoach();
echo json_encode($posts);
}
}
}
public function FetchCoach()
{
$query = $this->db->get('coach');
if(count($query->result() ) > 0)
{
return $query->result();
}
}