Php 我的mysql不工作我哪里做错了？

我试图根据数据库中的特定id从数据库中获取数据

这是我的密码。但它们在其他方面不起作用 $selectquery$resultsgetdata$countprodu

---

您忘记获取值，请尝试此操作

您需要使用mysql\u fetch\u assoc

---

试试这个我希望它能起作用

<?php
$profrom = $_GET['id'];
$selectquery = "SELECT * FROM tbl_name WHERE proid = '$profrom'";
$resultsgetdata = mysql_query($selectquery);
$countprodu= mysql_num_rows($resultsgetdata);
if($countprodu>0)
{
  while($row = mysql_fetch_array($resultsgetdata))
  {
    $proidid = $row['proid']; 
    $proidName = $row['proName'];
    $proidDescription = $row['proDescription'];
    $Category   = $row['proCategory'];
    $Price    = $row['Price'];
    $Photo1name = $row['Photo1name'];

    echo $proidid;
  }
}
?>

---

$selectquery=SELECT*FROM tbl\U名称，其中proid=.$profrom，使用当前查询字符串proid=$profrom而不是proid=actual id ex.1请格式化代码。这是非常难读的，甚至不清楚你在问什么。不工作怎么办？我希望现在一切正常？我没有告诉你@Dr.stitchy你忘了从查询结果中提取数据。为此使用mysql\u fetch\u数组。注意：-mysql已被弃用，请改用mysqli或pdoTry。这对您的标准很有用@利昂·马莱什

<?php
$profrom = $_GET['id'];
$selectquery = "SELECT * FROM tbl_name WHERE proid = '$profrom'";
$resultsgetdata = mysql_query($selectquery);
$countprodu= mysql_num_rows($resultsgetdata);
if($countprodu>0)
{
  while($row = mysql_fetch_assoc($resultsgetdata))
  {
    $proidid = $row['proid']; 
    $proidName = $row['proName'];
    $proidDescription = $row['proDescription'];
    $Category   = $row['proCategory'];
    $Price    = $row['Price'];
    $Photo1name = $row['Photo1name'];

    echo $proidid;
  }
}
?>

<?php
$profrom = $_GET['id'];
$selectquery = "SELECT * FROM tbl_name WHERE proid = '$profrom'";
$resultsgetdata = mysql_query($selectquery);
$countprodu= mysql_num_rows($resultsgetdata);
if($countprodu>0)
{
  while($row = mysql_fetch_array($resultsgetdata))
  {
    $proidid = $row['proid']; 
    $proidName = $row['proName'];
    $proidDescription = $row['proDescription'];
    $Category   = $row['proCategory'];
    $Price    = $row['Price'];
    $Photo1name = $row['Photo1name'];

    echo $proidid;
  }
}
?>